449 (g K) / 39.1 (g/mol K) = 11.5 mol K
To determine the number of moles of potassium in 449 g, you need to divide the mass (449 g) by the molar mass of potassium (39.1 g/mol). This calculation would give you the number of moles of potassium in 449 g.
The balanced equation for this reaction is: 2K3PO4 + 3Al(NO3)3 -> 6KNO3 + AlPO4. This indicates that 2 moles of potassium phosphate react with 2 moles of aluminum nitrate to produce 6 moles of potassium nitrate.
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
To find the number of moles in 449 g of potassium, divide the given mass by the molar mass of potassium. The molar mass of potassium (K) is approximately 39.10 g/mol. Therefore, 449 g divided by 39.10 g/mol is approximately 11.49 moles of potassium.
To determine the number of moles of potassium in 449 g, you need to divide the mass (449 g) by the molar mass of potassium (39.1 g/mol). This calculation would give you the number of moles of potassium in 449 g.
12 g of potassium is equivalent to 0,307 moles.
34,7 moles of potassium 1 356,7 g.
We need 3 moles of potassium perchlorate.
Four moles of potassium chlorate are needed.
0.1868 moles
The answer is 1 mole potassium chlorate.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
The balanced equation for this reaction is: 2K3PO4 + 3Al(NO3)3 -> 6KNO3 + AlPO4. This indicates that 2 moles of potassium phosphate react with 2 moles of aluminum nitrate to produce 6 moles of potassium nitrate.
The amount of potassium phosphate in the solution is 1.27 M * 0.343 L = 0.43561 moles.The chemical formula of potassium phosphate is K3PO4, so there is three times as many moles of potassium as there are moles of potassium phoshate in the molecule:0.43561 * 3 = 1.30683Answer: 1.31 moles