7: Molecules of HCl and KCl have the same number, 1, or chlorine atoms per mole; therefore, if HCl reacts completely with potassium, the same number of moles of potassium chloride as the number of moles of hydrogen chloride present will be formed. (For an ionic compound such as KCl, the term "formula unit" is preferable to "mole", but the mathematical consequences are the same.)
2.45 x 6.02 x 1023.4749 x 1025
234 grams
there are two moles produced in potassium nitrate.
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
.73 moles
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
About 0.013
2.45 x 6.02 x 1023.4749 x 1025
We need 8 moles potassium chloride.
12 g of potassium is equivalent to 0,307 moles.
234 grams
there are two moles produced in potassium nitrate.
34,7 moles of potassium 1 356,7 g.
The answer is 0,175 moles.
We need 3 moles of potassium perchlorate.
Four moles of potassium chlorate are needed.