3.4g AgNO3 @ 107.9 g Ag / 169.9 g/mol AgNO3 = 2.159 g Ag
youir answer ( 2 sig figs) : 2.2 grams of Ag
2.2 g
AgNO3: 107.87 + 14.00 + 16.00 * 3 = 169.87 g/mol
Can't say, since "o" is not an element. However: Ag3N is Silver Nitride AgNO2 - Silver Nitrite AgNO3 - Silver Nitrate
AgNO3
The molar mass of silver nitrate is 169,87 g.2 x 169,87 = 339,74 g
2.2 g
The formula for silver nitrate is AgNO3.
The silver nitrate solution (AgNO3) provides the silver in silver chloride.
AgNO3: 107.87 + 14.00 + 16.00 * 3 = 169.87 g/mol
Can't say, since "o" is not an element. However: Ag3N is Silver Nitride AgNO2 - Silver Nitrite AgNO3 - Silver Nitrate
AgNO3
The molar mass of silver nitrate is 169,87 g.2 x 169,87 = 339,74 g
Its name is silver nitrate octahydrate. silver(Ag) nitrite(NO2) * octahydrate (8H2O)
the compound is chemically AgNO3, by mass, that would mean silver nitrate is 63% elemental silver. By volume, silver is denser than nitrogen or oxygen and would be less than 63%.
AgNO3
AgNO3
agno3