32.4
4314.9 grams
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
600 grams
1,000 grams = 1 kilogram 2,000 grams = 2 kilograms 3,000 grams = 3 kilograms . . . 6,000 grams = 6 kilograms 7,000 grams = 7 kilograms (That's more than 6 kilograms.)
i think it equals .120 grams
The percent concentration is 13,75 %.
13,75 % NaCl
Haemocyanins are a group of proteins.
This is the number of grams of solute in 100 grams of solution. As an example, a 5%w/w solution in water is prepared by dissolving 5 grams of solute in water and then adding further water with mixing until the final weight is 100 gram.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
The percentage of silver nitrate by weight is 100[5.48/(5.48 + 25.0)] = 18.0 %, to the justified number of significant digits.
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
0,64 moles (26,87 g) of NaF can't be dissolved in 63,5 g water; the solubility of NaF is 40,4 g/L at 20 oC.
That depends on how much solvent you are dissolving the 9 grams of salt in.
40.8 grams
by dissolving the amount you want in mole or grams in one dm3 of water