The percentage of nitrogen is 29,16 %.
To calculate the mass percent of nitrogen in ammonium carbonate (NH4)2CO3, first find the molar mass of the compound: 2(N) + 8(H) + 1(C) + 3(O) = 96 g/mol. The molar mass of nitrogen in the compound is 2(N) = 28 g/mol. To find the mass percent of nitrogen, divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100: (28 g/mol / 96 g/mol) x 100 = 29.2%.
The mass percent of nitrogen in ammonium carbonate NH42CO3 is 29,166 %.
The molar mass of ammonium carbonate is 96 g/mol (NH4)2CO3. The molar mass of nitrogen in the compound is 14 g/mol. Therefore, the mass percent of nitrogen in ammonium carbonate is (2*14 g/mol / 96 g/mol) * 100% = 29.2%.
To calculate the mass percent of nitrogen in ammonium carbonate ((NH4)2CO3), first find the molar mass of the compound: (2 x 14) + 12 + 3 x 16 = 96 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. The mass percent of nitrogen in (NH4)2CO3 is (2 x 14) / 96 x 100 = 29.2%.
Ammonium nitrate has a percent composition of approximately 35% nitrogen and 69.3% oxygen. The remaining percentage is made up of hydrogen and ammonium ions.
Ammonium hydrogen sulfate, (NH4)HSO4, contains one nitrogen atom in the ammonium ion. To calculate the percentage of nitrogen by mass, you would find the molar mass of nitrogen in the compound and divide it by the molar mass of the entire compound, then multiply by 100 to get the percentage.
Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms per formula unit. One mole of (NH4)2S contains 2 moles of nitrogen. Therefore, in 4.444 moles of (NH4)2S, there are 8.88 moles of nitrogen. The percent of nitrogen in the compound would be (8.88 moles / 4.444 moles) * 100%, which is 200%.
14.58%
Ammonium nitrate contains 35% nitrogen by weight.
Can you be more specific? Percent composition is usually the percent of an element in a compound.
Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms. One mole of (NH4)2S contains 2 moles of nitrogen. In 8.941 mol of (NH4)2S, there are 8.941 x 2 = 17.882 mol of nitrogen. To find the percent of nitrogen by weight, you would compare the molar mass of nitrogen to the molar mass of the compound and then multiply by 100.
Ammonium nitrate has a percent composition of approximately 35% nitrogen and 69.3% oxygen. The remaining percentage is made up of hydrogen and ammonium ions.
The percent by mass of nitrogen in NH4NO3 is 35.0%.
Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms per formula unit. One mole of (NH4)2S contains 2 moles of nitrogen. Therefore, in 4.444 moles of (NH4)2S, there are 8.88 moles of nitrogen. The percent of nitrogen in the compound would be (8.88 moles / 4.444 moles) * 100%, which is 200%.
No, 10 percent ammonia is not considered a quaternary ammonium compound. Quaternary ammonium compounds have four organic substituents bonded to a nitrogen atom, whereas ammonia (NH3) only has three hydrogen atoms bonded to a nitrogen atom.
it so very easy you can answer that joke the answer is percent of sulfur in ammonium sulfate
The chemical formula of Ammonium sulfate is (NH4)2SO4. The first step to these problems is finding all the atomic weights of the elements involved (including how many atoms of each element there is) and then adding them all up to get the total molecular mass of ammonium sulfate.Nitrogen = 14.0 × 2 = 28.0 gramsHydrogen = 1.00 × 8 = 8.00 gramsSulfur = 32.1 gramsOxygen = 16.0 × 4 = 64.0 grams-------------------------------------------Ammonium sulfate = 132.1 gramsThen to figure out the percentage of nitrogen in the compound, take the total mass of nitrogen and divide it by the total mass.Mass of nitrogen ÷ mass of ammonium sulfate = % nitrogen28.0 ÷ 132.1 = .212 = 21.2% nitrogen in ammonium sulfate(NH4)2SO4Percentage nitrogen by mass=(Molar mass of nitrogen)/(Molar mass of ammonium sulfate)*100In ammonium sulfate there are 2 Nitrogens, 8 Hydrogens, 4 Oxygens and 1 Sulfur, and their molar masses are 14, 1, 16 and 32 respectively. So, by dividing the molar mass of nitrogen in the compound by the total molar mass of the compound and multiplying it by one hundred we get the percentage of nitrogen.(14*2)/(14*2+1*8+16*4+32)*100= 21.2121...=21%
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The percent of nitrogen in sodium nitrate is 16,47 %.