The ratio mass of chlorine/mass of sodium is 1,5.
Sodium is 39,66583 %, chlorine 60,33417 %; the ratio Cl/Na is 1,521.
Sodium chloride is formed from sodium and chlorine.
The molar mass of sodium chloride is 58, 439 769 28 g.
Sodium chloride has a 1 to 1 ratio of its constituent atoms, sodium and chlorine. Sodium chloride, table salt, is a two-atom molecule. One atom of sodium is bonded to one atom of chlorine. The two atoms have combine to make a molecule of salt in a one-to-one ratio.
Sodium Chloride is a compound made up of Na+ and Cl- ions in a lattice arrangement in a 1:1 ratio
This question can be answered with the equation n = m ÷ M (where n is the number of mol's, m is te mass in grams and M is the Molar Mass of Sodium Chloride). Now, sodium chloride's molecular formula is written as, NaCl Now if we think of this formula as representing a ratio of elements within the compound, we can see that, NaCl : Cl = 1 mole of sodium chloride molecules : 1 mole of Chloride atoms So, as we know the mol ratio for this molecule, we can establish the mass of sodium in 11.7g of sodium chloride by first calculating the number of moles of Sodium chloride in 11.7g of the substance, so then moles = mass of sodium chloride ÷ Molar mass of sodium chloride = 11.7 ÷ 58.44277 = 0.20019584971759552122529442050745 moles (note that in stochiometry i personally prefer not to round numbers until the end of the question Now by applying this number to the mol ratio, we can calculate the number of moles of sodium in sodium chloride 1 mole of sodium chloride molecules : 1 mole of Chloride atoms =0.20019584971759552122529442050745 : 0.20019584971759552122529442050745 Now that we have established that the number of moles of of sodium in 11.7g of sodium chloride is 0.20019584971759552122529442050745 mol, the mass of sodium in 11.7g of sodium chloride can be calculated with the formula, m = n M = mass of sodium in 11.7g of sodium chloride = 0.20019584971759552122529442050745 X 23 = 4.6045045435046969881817716716713g (all decimal places)
Sodium chloride is dissolved and dissociated in water: NaCl--------------Na+ + Cl-
There are two main ones -sodium and chlorine making up sodium chloride which is table salt. However, there are traces of other materials (present and deliberately added)- flow agents for example.
Sodium: Na Chlorine: Cl Sodium Chloride: NaCl
Sodium from the cation sodium (Na+) and chloride (Cl-) from the anion.
by reacting the brome in the the sodium chloride: Br + NaCl----- BrNa + cL---------cl+naocl= naocl
NaCl, table salt, is made of Sodium (Na) and Chlorine (Cl) in a one to one ratio.
The sodium chloride dissociates into its individual ions; sodium cations, Na+ and chloride anions, Cl-.
Calculate the percent by weight of sodium (Na) and chlorine (Cl) in sodium chloride (NaCl) * Calculate the molecular mass (MM):MM = 22.99 + 35.45 = 58.44 * Calculate the total mass of Na present:1 Na is present in the formula, mass = 22.99 * Calculate the percent by weight of Na in NaCl:%Na = (mass Na ÷ MM) x 100 = (22.99 ÷ 58.44) x 100 = 39.34% * Calculate the total mass of Cl present:1 Cl is present in the formula, mass = 35.45 * Calculate the percent by weight of Cl in NaCl:%Cl = (mass Cl ÷ MM) x 100 = (35.45 ÷ 58.44) x 100 = 60.66% The answers above are probably correct if %Na + %Cl = 100, that is,39.34 + 60.66 = 100.
Sodium chloride is NaCl because sodium (Na) forms the positive ion and chlorine (Cl) forms the negative ion and the two combine in a 1:1 ratio.