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What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
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87.2 grams of glucose burned in 87.2 grams oxygen what is limiting reactant?
Glucose
For each of the following precipitation reactions calculate how many grams of the first reactant are necessary to completely react with 56.5 g of the second reactant?
12.1g/moles
For the following equation SnO2 plus 2H2 equals Sn plus 2H20 how many grams of Sn is formed if 12.5 grams of the first reactant is used?
9,846 g of tin (Sn)
If you have 3 64 grams of H2 how many grams of NH3 can be produced?
The answer is 20,664 g ammonia.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
If there are 4 grams of reactant how many grams of product are produced by the chemical reaction?
4
If 25.0 grams of potassium chlorate decomposes, how many grams of potassium chloride will be produced What is the limiting reactant?
I Don't knows Sorry
What is the limiting reactant when 3.14g of nitrogen react with 2.79g of hydrogen to produce ammonia and how many grams of ammonia are produce?
Nitrogen is the limiting reactant and 4.15g of ammonia are produced.
In a chemical reaction 300 grams of reactant A are combined with 100 grams of reactant B . both A and B reactant to completion. how much will the product weigh?
200
What is the reactant of 10.0 grams of total mass What is the chemical reaction?
It is possible to have ten grams of anything. Specifying the total weight tells you nothing about which reactant you have or what reaction it will undergo.
87.2 grams of glucose burned in 87.2 grams oxygen what is limiting reactant?
Glucose
When 10.0 grams of calcium reacts with 20.0 grams of chlorine gas, how many grams of calcium chloride can be produced Which reactant is in excess and which is the limiting reactant?
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
When there are 3 grams of carbon and 8 grams of oxygen if all of the carbon and oxygen reacted how many grams of carbon dioxide are produced?
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
Ammonia gas NH3 can be manufactured by combining hydrogen and nitrogen gases If 28 g of nitrogen and 7 g of hydrogen are available how many grams of ammonia can be produced?
2g
How many grams of H 2O will be produced if 750 grams of Fe are produced?
322 grams.
How many grams of NaCL are produced when 80.0 grams of O2 are produced?
96.75 grams of NaCl
How many grams of water can be produced from 50 grams of hydrogen and 300 grams of oxygen?
2H2 + O2 ===> 2H2O50 grams H2 x 1 mole H2/2 g = 25 moles H2300 grams O2 x 1 mole O2/32 g = 9.375 moles O2Limiting reactant is O2, so maximum moles of H2O formed = 9.375 O2 x 2H2O/1 O2 = 18.75 molesgrams H2O = 18.75 moles H2O x 18 g/mole = 337.5 g H2O = 340 g (to 2 significant figures)
