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1gb = 1024 mb.
You cannot address 1GB memory with the 8085 or the 8086/8088 without some kind of external demultiplexor that is software controlled. The address bus on the 8085 is 16 bits, giving addressibility of 64KB; while the address bus on the 8086/8088 is 20 bits, giving addressibility of 1MB. To address 1GB, you need a 30 bit address bus.
It requires 30 address bits to address 1GB of RAM.230 = 1,073,741,824
1GB has way more memory. 1GB is 1000 MB. so 512 MB is about half of 1GB
Storage cost per byte is very small number in cents. For example 1GB RAM cost around $AU20 today. The cost per byte would 20/1,073,741,824. 1GB=1,073,741,824bytes
You need 30 address lines to access 1G of memory. 230 = 1,073,741,824. log2 (1,073,741,824) = 30.
I think the 1gb 2rx16 is best!
4BG is not a term used for memory, as memory is stored in bytes. So the answer to your question is 1GB.
32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;
Ghz is Giga hertz, a type of frecuency commonly used in processor nomenclature. GB is Giga byte, used in memory. 1GB = 1000MB (mega byte) 1Ghz= 1000Mhz 80GB= 80000MB= A butt load of bytes :)
if you are asking for terra byte then 1024 byte = 1KB 1024 KB = 1MB 1024 MB = 1GB 1024 GB = 1 TB (tera byte)..
1GB