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Molar heat of combustion of ethanol = -1366.8 kJ/mol C2H5OH
Wiki User
∙ 13y ago
Wiki User
∙ 14y ago2010 KJ/mol is the molar heat of combustion of propanol
Wiki User
∙ 13y agoWiki User
∙ 16y agoThe molar heat of combustion of pentanol is 3329 kJ mol-1 according to
http://www.creative-chemistry.org.uk/gcse/documents/Module7/N-m07-24.pdf
Wiki User
∙ 14y ago-304 kJ mol-1
Wiki User
∙ 15y agoit is 1761 kJ/mol
Wiki User
∙ 13y agoroughly 150kj/mol
Wiki User
∙ 11y ago-2005.8
Wiki User
∙ 14y ago1403KJmol-1
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Why does oxygen gas not have an enthalpy of formation but ozone does?
Ozone gas has enthalpy of formation. It is due to the high altitude.
What is the relation of the molar heat of fusion to the molar heat of vaporization?
Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).
What is the standard molar enthalpy change of combustion for coconut oil?
Coconut oil is a mixture not a compound.
WHAT IS THE STANDARD HEAT FORMATION OF POTASSIUM HYDROXIDE (S)?
The standard enthalpy of formation for potassium hydroxide is -425,8 kJ/mol.
True or false The molar enthalpy values and fusion stay the same if you were to reverse the process?
False, I'd think.
What is the standard molar enthalpy of formation for ammonium chloride aq?
-299.65 kJ/mole
What is the heat released during the synthesis of one mole of compound from its elements?
Molar heat (or enthalpy) of formation.
How does molar enthalpy of fussion of ice compare with the molar enthalpy of fussion of other solids?
it is relatively large
How many moles of propanol C3H8O are there in 42.1g of propanol?
42.1g/ 59g/mol (grams/molar mass of C3H8O)
What is the difference of enthalpy of formation and the enthalpy of combustion?
Enthalpy of combusion is energy change when reacting with oxygen. Enthalpy of formation is energy change when forming a compound. But some enthalpies can be equal.ex-Combusion of H2 and formation of H2O is equal
Equation for the heat of formation of carbon disulphide?
C + 2S -> CS2 Enthalpy of formation is the change in enthalpy for the formation of a substance from its elements.
What is molar enthalpy change?
Molar bond enthalpy shows the change in a bond association. For example, if one mole of bond is broken, the energy change that results is DHd (degree).
Why does oxygen gas not have an enthalpy of formation but ozone does?
Ozone gas has enthalpy of formation. It is due to the high altitude.
What does the negative sign on the value of an enthalpy of formation indicate?
A negative enthalpy of formation indicates that energy is evolved.
Molar Enthalpy of Candle Wax C25H52?
-1308.3 kJ
What is the basic difference between enthalpy of formation?
Standard Heat (Enthalpy) of Formation, Hfo, of any compound is the enthalpy change of the reaction by which it is formed from its elements, reactants and products all being in a given standard state.By definition, the standard enthalpy (heat) of formation of an element in its standard state is zero, Hfo = 0.Standard Molar Enthalpy (Heat) of Formation, Hmo, of a compound is the enthalpy change that occurs when one mole of the compound in its standard state is formed from its elements in their standard states.Standard Enthalpy (Heat) of Reaction, Ho, is the difference between the standard enthalpies (heats) of formation of the products and the reactants.Ho(reaction) = the sum of the enthalpy (heat) of formation of products - the sum of the enthalpy (heat) of formation of reactants: Ho(reaction) = Hof(products) - Hof(reactants)To calculate an Enthalpy (Heat) of Reaction:Write the balanced chemical equation for the reaction Remember to include the state (solid, liquid, gas, or aqueous) for each reactant and product.Write the general equation for calculating the enthalpy (heat) of reaction: Ho(reaction) = Hof(products) - Hof(reactants)Substitute the values for the enthalpy (heat) of formation of each product and reactant into the equation. Remember, if there are 2 moles of a reactant or product, you will need to multiply the enthalpy term by 2, if molar enthalpies (heats) of formation are used.Standard Enthalpy (Heat) of FormationExample: Standard Enthalpy (Heat) of Formation of WaterThe standard enthalpy (heat) of formation for liquid water at 298K (25o) is -286 kJ mol-1. This means that 286 kJ of energy is released when liquid water, H2O(l), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(l) Hfo = -286 kJ mol-1The standard enthalpy (heat) of formation of water vapour at 298K (25o) is -242 kJ mol-1.This means that 242 kJ of energy is released when gaseous water (water vapour), H2O(g), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(g) Hfo = -242 kJ mol-1
What is Enthalpy of formation of chloroform?
There are several different measures of enthalpy. See link for some information.
