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PV=nRTR = 0.08205746 Latm/kmol

20C + 273.15 = 293.15K

n = (0.090 ATM * 1.8 L) / ( 0.08205746 Latm/kmol * 293.15K)

n = 0.00673mol

589g / 0.00673 mol

87459.75 g/mol

well this is how you do it

now this is an unbelievable high molar mass so check the values of mass and pressure and you may need to recompute

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Q: What is the molar mass of an unknown gas in a 1.8L container if 589 g has a pressure of . .090atm at 20C?
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