The molecular Mass for sodium bicarbonate is 22.989770 + 1.00794 + 12.0107 + 15.9994*3
Sodium Carbonate is Na2CO3
and therefore, its molar mass is
sodium Na= 2x23g=46g
Carbonate CO3 = 12+48 = 60
60+46 = 106g
That Depends on what is the mass of sodium carbonate NaCO3
1mol NaCO3 = 83g
Na2CO3 is a basic compound. Molar mass for it is 106gmol-1.
The molar mass of the hydrated sodium carbonate - Na2CO3.10H2O - is 286,1416 g.
The formula for sodium carbonate is Na2CO3 and the molar mass is 105,9888 g (for the anhydrous salt).
234 grams :)
the answer is 2
The formula mass of sodium carbonate, Na2CO3 is 2(23.0)+12+3(16) = 106.0 Amount of sodium carbonate = 2.12/106.0 = 0.0200mol
234 grams
The formula mass of sodium carbonate, Na2CO3 is 2(23.0)+12+3(16) = 106.0Amount of sodium carbonate = mass of sample / formula mass = 4/106.0 = 0.0377mol
234 grams :)
the answer is 2
424 divided by the atomic mass of sodium carbonate 105.99 g/mol
Dividing by the molar mass of sodium carbonate, we deduce that there are 4.25 x 10-5 moles in 4.5 x 10-3 grams of sodium carbonate.
The formula mass of sodium carbonate, Na2CO3 is 2(23.0)+12+3(16) = 106.0 Amount of sodium carbonate = 2.12/106.0 = 0.0200mol
6into23equals 138 6into23equals 138
0,028 moles carbonic are obtained.
234 grams
The formula mass of sodium carbonate, Na2CO3 is 2(23.0)+12+3(16) = 106.0Amount of sodium carbonate = mass of sample / formula mass = 4/106.0 = 0.0377mol
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
The carbonate ion is the conjugate base of a diprotic acid. If you react an equal number of moles of hydrochloric acid and sodium carbonate, the carbonate will only be partially neutralized you will get a mixture of sodium chloride and sodium bicarbonate. HCl + Na2CO3 --> NaHCO3 + NaCl Only by adding twice as many moles of HCl will you completely neutralize the sodium carbonate. 2HCl + Na2CO3 --> 2NaCl + H2O + CO2
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