0
The moLaRity of this solution ie 2 mol/L or 2M KI (it is a 'two molair potassium iodide' solution)
Wiki User
∙ 10y ago
Wiki User
∙ 10y agoYes, you will get a 2M solution because M=mol/liter and you are putting in 2 moles into 1 liter
Wiki User
∙ 10y agoBy it's definition, molarity means how many moles are in a litre. As you already have your moles and it is per litre already, the answer is 2 molar.
Wiki User
∙ 8y agoThis solution is 2 molar (2 mol/L).
Wiki User
∙ 12y ago2m
Wiki User
∙ 10y ago8 mles
Anonymous
2 mol
Add your answer:
Earn +20 pts
What is the molarity of 495 mL solution containing 21.1 g of potassium iodide?
We have 495 ml, but we need to convert this to 1000, so we divide by 495 and multiply by 1000. We also do this to 21.1g. 21.1/495*100 is 42.626g. KI's molecular weight is 166g/mol. 42.626/166 is 0.2568 molar.
Will lead II iodide be more or less soluble in a solution of 0.1M KI than it will be in pure water?
If KI is present in a solution and PbI2 is being dissolved in it, there will be a greater concentration of I, this will cause the equilibrium to shift left, away from the increase, according to Le Chatelier's Principle. Shifting the equilibrium left will result in a greater mass of solid PbI2. Therefore the solubility of PbI2 will decrease in a solution of KI.
What is the chemical reaction for ethanol mixed with iodine?
Potassium iodide does not react with water; it only dissolves. The equation for this is KI(s) --> K+(aq) + I-(aq).
What substance produced in the reaction of chlorine water and KI was confirmed by its reaction with starch?
Cl2+KI=
How many grams of KI are in 25.0ml of a 3.0 (mv) KI solution?
55 ml of a 4.05 M solution of KI solution contains 55*4.05=222.75 millimoles. 20.5 ml of the diluted solution contains 3.8g of KI,so no.of moles of KI=3.8/(mol.wt of KI=165.9) is 22.9 millimoles. molarity of final diluted solution=22.9/20.5=1.117M since the no. of moles of KI present in initial and final solution are same. let.V(in ml) be the final volume of diluted solution. 222.75/V=1.117 V=199.41 ml final volume =199.41 ml
What is the molarity of 67.94 mL aqueous solution containing 2.822 g of KI?
Molarity = moles of solute/Liters of solution. get moles KI 2.822 grams KI (1 mole KI/166 grams) = 0.017 moles KI ( 67.94 ml = 0.06794 Liters ) Molarity = 0.017 moles KI/0.06794 Liters = 0.2502 M KI
What is the molarity of a solution prepared by dissolving 2.41 g of potassium iodide KI in 100 mL of water?
Find moles potassium iodide first.2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KIMolarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )Molarity = 0.01452 moles KI/0.1 Liters= 0.145 M KI solution================
To 225 mL of a 0.80M solution of KI a student adds enough water to make 1.0 L of a more dilute KI solution What is the molarity of the new solution?
0.18M
What mass of KI is present in 276 mL of a 0.50 M solution?
V*c*M = 276(mL)*0.001(L/mL)*0.50(mol KI/L)*166.0(g KI/mol KI) = 22.9 g KI
When the ionic compound KI is dissolved in water the you- ions are pulled into solution by the attraction between?
When the ionic compound of potassium ions are dissolved in water the hydroxyl ions of water which are negatively charged, will attract the positive potassium ions.
How do you draw a diagram to show how potassium iodide dissolves in water?
Orizontal ax: the quantity of KI dissolved in grams Vertical ax: temperature in 0C
How many moles of KI are present in 500 ml of a 0.2M solution?
The answer is 0,1 mol.
What is the role of potassium iodide in the formulation of strong iodine solution?
The role of KI in the preparation of strong iodine solution is to enhance the solubility of iodine crystals in water. Iodine is generally not soluble in water. The KI is added to help the iodine to be dissolved. -College Chemistry professor
What is the molarity of 495 mL solution containing 21.1 g of potassium iodide?
We have 495 ml, but we need to convert this to 1000, so we divide by 495 and multiply by 1000. We also do this to 21.1g. 21.1/495*100 is 42.626g. KI's molecular weight is 166g/mol. 42.626/166 is 0.2568 molar.
How many grams of iodine are produced when 0.72 mol of fluorine reacts with potassium iodide KI 2 KI F2 -- 2 KF I2?
182.88
What is the molar mass of KI?
The gram formula mass for KI or potassium iodide is 166.0027 grams per mole. You find this mass by multiplying the atomic masses of potassium and iodine by the number of atoms given for each in the formula, and then adding these two results.
What is the difference between povidone and tincture iodine?
Povidone Iodine is a mixture of Polyvinylpyrrolidone and Iodine. Tincture of Iodine is a mixture of Elemental Iodine + KI/NaI dissolved in a mixture of ethanol & water
