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It is not important whether this '200 ml of solution' is countable without or without the hydrated compounds contribution of H2C2O4.2H2O

At first find moles of this

3.78 grams H2C2O4 . 2H2O ( 1 mole cpd./126.068 grams)

= 0.02998 moles H2C2O4 . 2H2O

Since Molarity = moles of solute/Liters of solution ( 200 ml = 0.200 Liters )

Molarity = 0.02998 moles H2C2O4 . 2H2O/0.200 Liters

= 0.150 M H2C2O4.2H2O

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10y ago
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10y ago

3.78 (g H2C2O4.2H2O) / 126.068 (g.mol-1 H2C2O4.2H2O) = 0.02998 (mol H2C2O4.2H2O)

Molarity = moles of solute per Liters of solution

= 0.02998 (mol H2C2O4.2H2O) / 0.200 (Liters) = 0.150 (mol.L-1 H2C2O4.2H2O)

Answer: Molarity = 0.150 M

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13y ago

Molar mass H2C2O4.2H2O =126.0658 g/mol

2.38g = 2.38/126.0658 = 0.0189mol dissolved in 200ml solution.

Molarity = 1000/200*0.0189 = 0.094M

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8y ago

molar mass H2C2O4x2H2O = 2+24+64+36 = 126 g/mole
moles = 2.38 g x 1mol/126 g = 0.0189 moles
molarity = 0.0189 moles/0.200 L = 0.0944 M

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8y ago

The molarity of the oxalic acid is 0,094.

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10y ago

molarity of known H2C2O4

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Q: What is the molarity of H2C2O4 2H2O solution?
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2.431 g of h2c2o4 x 2h2o was obtained and dissolved in enough dI water to form 250.0 ml of solution what is the concentration of the resulting of h2c2o4 solution?

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