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It is not important whether this '200 ml of solution' is countable without or without the hydrated compounds contribution of H2C2O4.2H2O
At first find moles of this
3.78 grams H2C2O4 . 2H2O ( 1 mole cpd./126.068 grams)
= 0.02998 moles H2C2O4 . 2H2O
Since Molarity = moles of solute/Liters of solution ( 200 ml = 0.200 Liters )
Molarity = 0.02998 moles H2C2O4 . 2H2O/0.200 Liters
= 0.150 M H2C2O4.2H2O
What else can I help you with?
What is the equation for hydrated oxalic acid and sodium hydroxide?
The equation for the reaction between hydrated oxalic acid (H2C2O4·2H2O) and sodium hydroxide (NaOH) is: H2C2O4·2H2O + 2NaOH → Na2C2O4 + 4H2O
What is the net ionic equation of H2C2O4 plus KOH?
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
What is the relationship between weight and molarity in a solution?
The relationship between weight and molarity in a solution is that weight is directly proportional to molarity. This means that as the molarity of a solution increases, the weight of the solute in the solution also increases. Conversely, as the molarity decreases, the weight of the solute in the solution decreases.
How to find the molarity of a solution?
To find the molarity of a solution, divide the number of moles of solute by the volume of the solution in liters. Molarity (M) moles of solute / liters of solution.
What is the product of NaOH H2C2O4?
The product of the reaction between NaOH and H2C2O4 is sodium oxalate (Na2C2O4) and water (H2O). This is a double displacement reaction where the sodium ion from NaOH replaces the hydrogen ion in oxalic acid (H2C2O4) to form the salt sodium oxalate.
2.431 g of h2c2o4 x 2h2o was obtained and dissolved in enough dI water to form 250.0 ml of solution what is the concentration of the resulting of h2c2o4 solution?
Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity
If 25.5mg of oxalic acid dihydrate are dissolved in 1.00 ml of solution what is the molarity of the resulting solution?
To calculate the molarity, you need to know the molar mass of oxalic acid dihydrate (C2H2O4•2H2O) which is approximately 126.07 g/mol. First, convert 25.5 mg to grams (0.0255 g), then calculate the number of moles using the molar mass. Next, divide the number of moles by the volume of solution in liters (1.00 ml = 0.001 L) to find the molarity which is 0.255 M.
What is the equation for hydrated oxalic acid and sodium hydroxide?
The equation for the reaction between hydrated oxalic acid (H2C2O4·2H2O) and sodium hydroxide (NaOH) is: H2C2O4·2H2O + 2NaOH → Na2C2O4 + 4H2O
What is the net ionic equation of H2C2O4 plus KOH?
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
Chemical formula for oxalic acid dihydrate?
The chemical formula of the oxalic acid is C2O4H2.
What is the relationship between weight and molarity in a solution?
The relationship between weight and molarity in a solution is that weight is directly proportional to molarity. This means that as the molarity of a solution increases, the weight of the solute in the solution also increases. Conversely, as the molarity decreases, the weight of the solute in the solution decreases.
Does the molarity of a solution decrease on raising the temperature of the solution?
If you raise a solution temperature the molarity will decrease.
How to find the molarity of a solution?
To find the molarity of a solution, divide the number of moles of solute by the volume of the solution in liters. Molarity (M) moles of solute / liters of solution.
How do you calculate the molarity of a solution?
To calculate the molarity of a solution, you divide the number of moles of solute by the volume of the solution in liters. The formula is: Molarity (M) moles of solute / liters of solution.
How to calculate the molarity of a solution?
To calculate the molarity of a solution, you divide the number of moles of solute by the volume of the solution in liters. The formula is: Molarity (M) moles of solute / liters of solution.
What is the product of NaOH H2C2O4?
The product of the reaction between NaOH and H2C2O4 is sodium oxalate (Na2C2O4) and water (H2O). This is a double displacement reaction where the sodium ion from NaOH replaces the hydrogen ion in oxalic acid (H2C2O4) to form the salt sodium oxalate.
What is the ethanol molarity in the solution?
To find the ethanol molarity in a solution, you would divide the moles of ethanol by the volume of the solution in liters. The formula for molarity is M moles of solute / liters of solution.
