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What is the molarity of a solution containing 90 moles of solute in 5000mL of solution?

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2012-01-11 22:20:52
2012-01-11 22:20:52

Molarity = moles of solute/Liters of solution ( 5000 ml = 5 Liters )

Molarity = 90 moles solute/5 Liters

= 18 M

--------------------the most concentrated possible

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The molarity of a solution containing 7,0 moles of solute in 523 mL of solution is 4.





Molarity is number of moles in solute. So molarity of this is 0.5mol-1.



Molarity = moles of solute/Liters of solution so, 959 milliliters = 0.959 Liters Molarity = 7.0 moles of solute/0.959 Liters = 7.3 M solute ===========


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Increasing the amount of the solute in the solution the molarity and the density of this solution increases.


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Molarity means moles in a litre. Therefore you need to divide by 3.95. 1.4/3.95 is 0.35443 molar.


Calculating molarity of this solution requires the variables of solute mass (in kilograms), molecular weight of the solute (in kilograms per mole), and solution volume to be known (in liters). In this example we only have the variables of a mass of .056 kilograms and volume of .959 liters.


Molarity= (number of moles of solute)/(volume of solution in dm3)


Molarity= No. of moles of solute/Volume of solution(in litre) or No. of moles of solute*1000/Volume of solution(in ml)




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