Chemistry
Acids and Bases

# What is the molarity of a solution containing 90 moles of solute in 5000mL of solution?

333435 ###### 2012-01-11 22:20:52

Molarity = moles of solute/Liters of solution ( 5000 ml = 5 Liters )

Molarity = 90 moles solute/5 Liters

= 18 M

--------------------the most concentrated possible

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## Related Questions The molarity of a solution containing 7,0 moles of solute in 523 mL of solution is 4.    Molarity is number of moles in solute. So molarity of this is 0.5mol-1.  Molarity = moles of solute/Liters of solution so, 959 milliliters = 0.959 Liters Molarity = 7.0 moles of solute/0.959 Liters = 7.3 M solute =========== It depends what the solute is. There is no way to determine the molarity without knowing that piece of information.  The molality of this solution is 1,905; to calculate the molarity you need the density of the solution. Molarity = moles of solute/Liters of solution ( 500.0 ml = 0.5 Liters ) Molarity = 0.75 moles/0.5 Liters = 1.5 M Molarity = moles of solute/Liters of solution ( 500.0 ml =0.500 Liters ) Molarity = 0.75 moles/0.500 Liters = 1.5 M ----------  Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ========== The molarity of a solution containing 7.0 moles of solute in 569mL of solution is a)81M b)0.081M c)12M D)4.0M The answer is C. 12M 7 x 1000/569 = 12.302 Molarity= moles of solute/volume of solution in liters, so the problem looks like this: 7/.569, which equals 12.302 M. Molarity = moles of solute/liters of solution Molarity = 7 moles solute/2 Liters solution = 3.5 M ====== You need to get it per litre. 250x4 will give you 1 litre, so 0.325x4 will give you your molarity. This gives a molarity of 1.3 (molar). Increasing the amount of the solute in the solution the molarity and the density of this solution increases. MOLARITY = mole of solute / L solution Molarity means moles in a litre. Therefore you need to divide by 3.95. 1.4/3.95 is 0.35443 molar. Calculating molarity of this solution requires the variables of solute mass (in kilograms), molecular weight of the solute (in kilograms per mole), and solution volume to be known (in liters). In this example we only have the variables of a mass of .056 kilograms and volume of .959 liters. Molarity= (number of moles of solute)/(volume of solution in dm3) Molarity= No. of moles of solute/Volume of solution(in litre) or No. of moles of solute*1000/Volume of solution(in ml) ###### ChemistryMath and Arithmetic Copyright © 2020 Multiply Media, LLC. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply.