.430
The molarity of acetone in water will depend on the concentration of acetone added to the water. Molarity is calculated as moles of solute divided by liters of solution. You would need to know the amount of acetone added to determine the molarity.
The normality of HCl can be calculated using the equation: Normality (HCl) * Volume (HCl) = Normality (NaOH) * Volume (NaOH). Solving for the normality of HCl gives 6.0N. The molarity of the HCl solution can be calculated using the formula: Molarity = Normality / n-factor. Assuming the n-factor for HCl is 1, the molarity of the HCl solution would be 6.0 M.
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
This solution will have a concentration of 0.3692 g/L for K2Cr2O7.
To find the molarity of Cu2+ ions, first calculate the moles of Cu2+ from the given mass of copper. Next, use the total volume of the solution to calculate the molarity. The molarity of Cu2+ ions in the solution is 0.377 M.
1.3g
What is the molarity of an HCl solution if 43.6 mL of a 0.125 M KOH solution are needed to titrate a 25.0 mL sample of the acid according to the equation below?
22
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
The molarity is 6.
The molarity of acetone in water will depend on the concentration of acetone added to the water. Molarity is calculated as moles of solute divided by liters of solution. You would need to know the amount of acetone added to determine the molarity.
first measure the volume of the sample solution needed to change the blue color of the DCPIP solution into colourless. then, weigh the mass of the sample solution. finally calculate the concentration by using the formula: volume required t change the color of DCPIP solution (dm) per mass of the sample solution (g)
In titrations, the end point is when you have brought the tested sample to absolute neutral. At this point, if you add one more drop of titrating solution to the sample, you would change the pH sufficient to change the color of the indicator in the sample. This is the point at which you can determine the pH of the original solution, by calculating back the amount of titrating solution you had to add to the sample to neutralize it.
Ammonium oxalate is added to a solution of calcium carbonate to precipitate calcium oxalate, which can then be used as a method to determine the amount of calcium present in the solution through gravimetric analysis. The reaction between calcium carbonate and ammonium oxalate forms a sparingly soluble calcium oxalate precipitate, which can be filtered out and weighed to calculate the calcium concentration in the original solution.
This solution will have a concentration of 0.3692 g/L for K2Cr2O7.
Yes, the reported molarity of the vinegar sample could be affected by an error in weighing because the amount of vinegar used in the titration would be inaccurate. This would result in a molarity calculation that is not precise and could lead to incorrect results.