Chemistry

Acids and Bases

Top Answer

It is not important whether this '200 ml of solution' is countable without or without the hydrated compounds contribution of H2C2O4.2H2O

At first find moles of this

3.78 grams H2C2O4 . 2H2O ( 1 mole cpd./126.068 grams)

= 0.02998 moles H2C2O4 . 2H2O

Since Molarity = moles of solute/Liters of solution ( 200 ml = 0.200 Liters )

Molarity = 0.02998 moles H2C2O4 . 2H2O/0.200 Liters

= 0.150 M H2C2O4.2H2O

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0Molar mass H2C2O4.2H2O =126.0658 g/mol 2.38g = 2.38/126.0658 = 0.0189mol dissolved in 200ml solution. Molarity = 1000/200*0.0189 = 0.094M

molar mass H2C2O4x2H2O = 2+24+64+36 = 126 g/molemoles = 2.38 g x 1mol/126 g = 0.0189 molesmolarity = 0.0189 moles/0.200 L = 0.0944 M

It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.

Molarity means moles per litre. Therefore you have to multiply by 5 in converting 200ml to a litre. 2*5 is 10 moles per litre.

3.78 (g H2C2O4.2H2O) / 126.068 (g.mol-1 H2C2O4.2H2O) = 0.02998 (mol H2C2O4.2H2O) Molarity = moles of solute per Liters of solution = 0.02998 (mol H2C2O4.2H2O) / 0.200 (Liters) = 0.150 (mol.L-1 H2C2O4.2H2O) Answer: Molarity = 0.150 M

20.0 g = 20.0 (g) / 40.0 (g/mol) = 0.500 mol200 mL = 200 (mL) / 1000 (mL/L) = 0.200 LFinally:molarity = 0.500 (mol) / 0.200 (L) = 2.50 mol/L

The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.

concentration = molarity molarity= moles/ volume (in liters) H=1g F= 19g 1gH+ 19gF= 20gHF 20gHF x (1 mol HF/ 20gHF) = 1mol HF 2.0x10^2ml= 200ml x (1L/1000mL)= .200L Concentration= 1 mol HF/ .200L Concentration= 5M

200ml of solution x 20% of alcohol = 40ml of alcohol..

By sugar I assume you mean sucrose. 15g in 200ml is the same as 75g in a litre. 75 / molecular weight of sucrose (342.3g/mol) is 0.2191 molar.

200ml of 8M NaOH is more concentrated

237.5 mL (200mL if you are keeping track of significant figures). Molarity is moles/liters. To make 900mL of a 2M solution, you need 1.8 moles of solute. There are 1.8 moles of solute in 237.5 mL of 8M solution.

10g/200ml=5g/100ml = 5% solution. Now read your Dosage and Calculations book and prepare for the test because it is Monday. Good luck!

You will get a salt solution.

Molarity = moles of solute/volume of solution 0.450 M = m/200ml = 90 millimoles, or, what we need; 0.09 moles 0.09 moles NaOH (39.998 grams NaOH/1 mole NaOH) = 3.60 grams of NaOH needed

2.6 litres (if a cup contains 200ml)

Density of etyl acetate

100 g per litre, which is 2.5 M.

Each 200ml contains- 1) Sodium Chloride= 250mg 2) Potassium Chloride= 30 mg 3) Sodium Citrate = 580 mg Calculate osmolarity of Sodium, Poatassium and Chloride

200ml of water is 0.882 of a cup200ml of water is 0.882 of a cup

200mL equates to 2dL (deciliters).

200ml is 0.88 of a cup200ml is 0.88 of a cup

A liter contains 1000 ml, therefor 200ml is 1/5 of a liter or 0,2l

You cannot convert 200mL to moles.

200ml is one fifth of a litre !

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