Chemistry
Acids and Bases

# What is the molarity of a solution that contains 3.78g H2C2O4 2H2O in 200ml of solution?

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It is not important whether this '200 ml of solution' is countable without or without the hydrated compounds contribution of H2C2O4.2H2O

At first find moles of this

3.78 grams H2C2O4 . 2H2O ( 1 mole cpd./126.068 grams)

= 0.02998 moles H2C2O4 . 2H2O

Since Molarity = moles of solute/Liters of solution ( 200 ml = 0.200 Liters )

Molarity = 0.02998 moles H2C2O4 . 2H2O/0.200 Liters

= 0.150 M H2C2O4.2H2O

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## Related Questions

Molar mass H2C2O4.2H2O =126.0658 g/mol 2.38g = 2.38/126.0658 = 0.0189mol dissolved in 200ml solution. Molarity = 1000/200*0.0189 = 0.094M

molar mass H2C2O4x2H2O = 2+24+64+36 = 126 g/molemoles = 2.38 g x 1mol/126 g = 0.0189 molesmolarity = 0.0189 moles/0.200 L = 0.0944 M

It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.

Molarity means moles per litre. Therefore you have to multiply by 5 in converting 200ml to a litre. 2*5 is 10 moles per litre.

3.78 (g H2C2O4.2H2O) / 126.068 (g.mol-1 H2C2O4.2H2O) = 0.02998 (mol H2C2O4.2H2O) Molarity = moles of solute per Liters of solution = 0.02998 (mol H2C2O4.2H2O) / 0.200 (Liters) = 0.150 (mol.L-1 H2C2O4.2H2O) Answer: Molarity = 0.150 M

20.0 g = 20.0 (g) / 40.0 (g/mol) = 0.500 mol200 mL = 200 (mL) / 1000 (mL/L) = 0.200 LFinally:molarity = 0.500 (mol) / 0.200 (L) = 2.50 mol/L

concentration = molarity molarity= moles/ volume (in liters) H=1g F= 19g 1gH+ 19gF= 20gHF 20gHF x (1 mol HF/ 20gHF) = 1mol HF 2.0x10^2ml= 200ml x (1L/1000mL)= .200L Concentration= 1 mol HF/ .200L Concentration= 5M

By sugar I assume you mean sucrose. 15g in 200ml is the same as 75g in a litre. 75 / molecular weight of sucrose (342.3g/mol) is 0.2191 molar.

237.5 mL (200mL if you are keeping track of significant figures). Molarity is moles/liters. To make 900mL of a 2M solution, you need 1.8 moles of solute. There are 1.8 moles of solute in 237.5 mL of 8M solution.

10g/200ml=5g/100ml = 5% solution. Now read your Dosage and Calculations book and prepare for the test because it is Monday. Good luck!

Molarity = moles of solute/volume of solution 0.450 M = m/200ml = 90 millimoles, or, what we need; 0.09 moles 0.09 moles NaOH (39.998 grams NaOH/1 mole NaOH) = 3.60 grams of NaOH needed

Each 200ml contains- 1) Sodium Chloride= 250mg 2) Potassium Chloride= 30 mg 3) Sodium Citrate = 580 mg Calculate osmolarity of Sodium, Poatassium and Chloride

200ml of water is 0.882 of a cup200ml of water is 0.882 of a cup

200mL equates to 2dL (deciliters).

200ml is 0.88 of a cup200ml is 0.88 of a cup

A liter contains 1000 ml, therefor 200ml is 1/5 of a liter or 0,2l