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∙ 15y agoUnless I've completely forgotten my chemistry, mole fraction is the fraction of moles of a particular solute of the entire number of moles in the solution. So for this question: formula weight of ethanol = 46.07 g/mol formula weight of water = 18.015 g/mol moles of ethanol = 47.5g / 46.07 g/mol = 1.0310 mol moles of water = 850g / 18.015 g/mol = 47.182 mol total number of moles in the solution = 1.0310 + 47.182 = 48.213 mol therefore, the mole fraction of ethanol is 1.0310 mol / 48.213 mol = 0.0214 hope this helps.
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∙ 15y agomansoor ahmed
613
First, calculate the volume percentages of ethanol and water in the solution. Since we know the density of both solvents, convert the percentages to mass (using density and volume). Then calculate the mole fraction of ethanol by dividing the moles of ethanol by the total moles of all components in the solution. Finally, calculate molality using the moles of solute (ethanol) and the mass of the solvent (water).
To calculate the mole fraction of water in the solution, we first need to determine the moles of water and ethanol present. Given that the solution is 57% water by mass, we can assume the remaining 43% is ethanol. From there, we can convert the mass percentages to moles using the molar masses of water and ethanol, and finally, calculate the mole fraction of water by dividing the moles of water by the total moles of the solution.
To find the mole fraction of ethanol, you first calculate the total moles of the solution, which is 3.00 + 5.00 = 8.00 moles. Then, you divide the moles of ethanol by the total moles of the solution: 3.00 moles / 8.00 moles = 0.375. So, the mole fraction of ethanol in the solution is 0.375.
To calculate the molarity, first calculate the concentration of ethanol in the solution using the mole fraction. Since the mole fraction of ethanol is 0.040, the mole fraction of water would be 1 - 0.040 = 0.960. Then, convert the mole fraction of ethanol to molality by dividing by the molar mass of ethanol. This gives you the molality of ethanol in the solution. Finally, since the density of water is 1 g/mL, the concentration in mol/L would be equal to the molality.
The answer is 31,05 g ethanol.
The mixture of ethanol in water is a homogeneous mixture because ethanol and water molecules mix evenly and form a single phase without easily visible boundaries between the two substances.
Almost no salt will dissolve in pure ethanol. If salt is added to a solution of ethanol and water, which are miscible, it may form a homogenous solution without being stirred.
The total volume of the solution is 10ml + 40ml = 50ml. The percentage concentration of ethanol in the solution is (10ml / 50ml) * 100% = 20%.
No this is not an ideal solution, because water and alcohol (ethanol) molecules interact rather complex resulting in eg. an azeotropic boiling point at 96% mixture
After 50 grams of water evaporate, you will be left with 50 grams of water in which the 3.0 grams of salt is dissolved. So, your solution will now contain 3.0 grams of salt dissolved in 50 grams of water.
A mixture of ethanol and water is known as a solution. Ethanol is soluble in water, which means it can mix evenly with water at the molecular level to form a homogeneous solution.
Divide the mass of the ethanol by the sum of the mass of the ethanol + that of the water and multiply by 100. Mass ethanol/(Mass ethanol + mass H2O) (x100)