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Unless I've completely forgotten my chemistry, mole fraction is the fraction of moles of a particular solute of the entire number of moles in the solution. So for this question: formula weight of ethanol = 46.07 g/mol formula weight of water = 18.015 g/mol moles of ethanol = 47.5g / 46.07 g/mol = 1.0310 mol moles of water = 850g / 18.015 g/mol = 47.182 mol total number of moles in the solution = 1.0310 + 47.182 = 48.213 mol therefore, the mole fraction of ethanol is 1.0310 mol / 48.213 mol = 0.0214 hope this helps.

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Q: What is the mole fraction of ethanol in a solution of 47.5 grams of ethanol in 850 grams of water?
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What are the mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume-The density of water is 1.00g per mL and that of ethanol is 0.789 grams per mL?

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