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Unless I've completely forgotten my chemistry, mole fraction is the fraction of moles of a particular solute of the entire number of moles in the solution. So for this question: formula weight of ethanol = 46.07 g/mol formula weight of water = 18.015 g/mol moles of ethanol = 47.5g / 46.07 g/mol = 1.0310 mol moles of water = 850g / 18.015 g/mol = 47.182 mol total number of moles in the solution = 1.0310 + 47.182 = 48.213 mol therefore, the mole fraction of ethanol is 1.0310 mol / 48.213 mol = 0.0214 hope this helps.

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Q: What is the mole fraction of ethanol in a solution of 47.5 grams of ethanol in 850 grams of water?

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The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.

0.375

0,98

The mixture water-ethanol is homogeneous.

The answer is 31,05 g ethanol.

Pure ethanol is slightly basic- about 7.9 However, a solution of ethanol and water is about 7,0- neutral

20%

It depends a bit on what information you are given. However, the principle is the same in all cases, although how you do the specific calculation may vary a bit.As an example, let's say we have a mixture of 5.00 grams of water and 10.0 grams of ethanol (C2H5OH). What is the mole fraction of the two components?The first thing we must do is convert the number of grams of each substance into moles. To do that, see the Related Question below:How do you convert from grams to moles and also from moles to grams?For water, we have:5.00 grams ÷ 18.015 grams/mole = 0.2775 moles H2OFor ethanol, we have:10.0 grams ÷ 46.068 grams/mole = 0.2171 moles C2H5OHNow we can find the mole ratio, which is defined as follows:Moles ratio of compound X = number of moles of X ÷ total number of moles in mixtureSo the mole ratio of water is: 0.2775 ÷ (0.2775 + 0.2171) = 0.561 or 56.1%and the mole ratio of ethanol is: 0.2171 ÷ ((0.2775 + 0.2171) = 0.439 or 43.9%Check your answer! The total mole ratio for all components MUST add up to 1.00:0.561 + 0.439 = 1.00 Yes!Note that the weight ratio was 1-to-2 (twice as much ethanol as water by weight), but the mole ratio was completely different.

Almost no salt will dissolve in pure ethanol. If salt is added to a solution of ethanol and water, which are miscible, it may form a homogenous solution without being stirred.

No this is not an ideal solution, because water and alcohol (ethanol) molecules interact rather complex resulting in eg. an azeotropic boiling point at 96% mixture

Divide the mass of the ethanol by the sum of the mass of the ethanol + that of the water and multiply by 100. Mass ethanol/(Mass ethanol + mass H2O) (x100)

The molality of ethanol will be 5,91.