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Empirical formula = C3H5O

Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07

Molar mass of molecular fomula = 114.15

n = Molar mass of molecular fomula/Molar mass of empirical formula

= 114.15/57.07

n = 2

Molecular formula = n(empirical formula)

Molecular formula = 2(C3H5O) = C6H10O2

Check:

6(12.01)+10(1.008)+2(16)= 114.14

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Q: What is the molecular formula for the unknown C3H5O?
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