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Empirical formula = C3H5O
Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07
Molar mass of molecular fomula = 114.15
n = Molar mass of molecular fomula/Molar mass of empirical formula
= 114.15/57.07
n = 2
Molecular formula = n(empirical formula)
Molecular formula = 2(C3H5O) = C6H10O2
Check:
6(12.01)+10(1.008)+2(16)= 114.14
What else can I help you with?
The combustion data for an unknown compound containing carbon hydrogen and oxygen was analyzed and the empirical formula for the unknown was found to be C3H5O The molar mass of the unknown was found?
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
An unknown sample with a molecular mass of 180.0g is analyzed to yield 40 percent C 6.7 percent H and 53.3 percent O What is the empirical formula and the molecular formula of this compound?
The empirical formula is CH2O. To find the molecular formula, you need to calculate the empirical formula weight (30 g/mol) and divide the molecular mass (180.0 g/mol) by the empirical formula weight to get 6. This means the molecular formula is (CH2O)6, which simplifies to C6H12O6, the molecular formula of glucose.
Determine the molecular formula for the unknown if the molecular mass is 60.0 amu and the empirical formula is CH2O.?
To determine the molecular formula from the empirical formula CH2O and given molecular mass of 60.0 amu, calculate the empirical formula mass: (12.01 g/mol for C) + 2(1.01 g/mol for H) + 16.00 g/mol for O = 30.02 g/mol. Then divide the given molecular mass by the empirical formula mass to find the factor by which the empirical formula must be multiplied to get the molecular formula: 60.0 amu / 30.02 g/mol ≈ 2. Next, multiply the subscripts in the empirical formula by this factor to find the molecular formula: 2(C)2(H)2(O) = C4H4O2, giving the molecular formula as C4H4O2.
What is the molecular formula for the unknown C2H4O?
That is a molecular formula.I can't off the top of my head think of any compound with that molecular formula, though. It's not methoxyethane or a propanol, because it's got one too few hydrogen atoms. It's not propanone or cyclopropanol or oxetane or a propenol, because it's got one too many hydrogen atoms.
What is the molecular formula of the principal molecular or ionic species present in glucose?
It is a molecular species with the formula C6H12O6
The combustion data for an unknown compound containing carbon hydrogen and oxygen was analyzed and the empirical formula for the unknown was found to be C3H5O The molar mass of the unknown was found?
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
Which chemical formula is both an empirical formula and a molecular formula?
Water (H2O) is a chemical formula that is both an empirical formula and a molecular formula. The empirical formula shows the simplest whole-number ratio of atoms in a compound, while the molecular formula shows the actual number of each type of atom in a molecule.
What is the empirical formula C12H6O3?
The principle for this kind of problem is to find the highest integer that is an integral factor of all the subscripts, then divide the subscripts by that integer. In this instance, 3 is the highest integer, since 15/3 = 5, a prime number, and 5 is not an integral factor of 9 or 3. Therefore, the empirical formula would be C3H5O.
What is the process to calculate the gram molecular weight of the unknown liquid?
To calculate the gram molecular weight of an unknown liquid, you need to determine the molecular formula of the liquid and then add up the atomic weights of all the atoms in the formula. This will give you the gram molecular weight of the unknown liquid.
What is the empirical formula for C9H15O3?
A molecular formula is identical to the empirical formula. The principle for this kind of problem is to find the highest integer that is an integral factor of all the subscripts then divide the subscripts by that integer. In this instance 3 is the highest integer. Therefore the empirical formula would be C3H5O.
How does one determine a molecular formula from the empirical form?
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
An unknown sample with a molecular mass of 180.0g is analyzed to yield 40 percent C 6.7 percent H and 53.3 percent O What is the empirical formula and the molecular formula of this compound?
The empirical formula is CH2O. To find the molecular formula, you need to calculate the empirical formula weight (30 g/mol) and divide the molecular mass (180.0 g/mol) by the empirical formula weight to get 6. This means the molecular formula is (CH2O)6, which simplifies to C6H12O6, the molecular formula of glucose.
Determine the molecular formula for the unknown if the molecular mass is 60.0 amu and the empirical formula is CH2O.?
To determine the molecular formula from the empirical formula CH2O and given molecular mass of 60.0 amu, calculate the empirical formula mass: (12.01 g/mol for C) + 2(1.01 g/mol for H) + 16.00 g/mol for O = 30.02 g/mol. Then divide the given molecular mass by the empirical formula mass to find the factor by which the empirical formula must be multiplied to get the molecular formula: 60.0 amu / 30.02 g/mol ≈ 2. Next, multiply the subscripts in the empirical formula by this factor to find the molecular formula: 2(C)2(H)2(O) = C4H4O2, giving the molecular formula as C4H4O2.
If an unknown hydrate MgCl2 and bullxH2O has a molecular mass of 203.30 gmol what is the numeric value of x in the formula?
This formula is for magnesium chloride hexahydrate: MgCl2.6H2O.
A multiple of an empirical formula is often called what?
molecular formula :]-kyrstiann dynae :]
What is the molecular formula for the unknown C2H4O?
That is a molecular formula.I can't off the top of my head think of any compound with that molecular formula, though. It's not methoxyethane or a propanol, because it's got one too few hydrogen atoms. It's not propanone or cyclopropanol or oxetane or a propenol, because it's got one too many hydrogen atoms.
What is the molecular formula of the principal molecular or ionic species present in glucose?
It is a molecular species with the formula C6H12O6
