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What is a combustion analysis used for?
Combustion analysis is used in chemistry to determine the elementary form of a pure compound. This is done by using a form of heating the sample so the results can be properly analyzed.
What is the empirical formula for a molecule containing 46.8 Si and 53.2 O?
The empirical formula would be SiO2. This is because the ratio of Si to O in the molecule is 1:2, which simplifies to SiO2.
Which could represent the empirical and the formula of a given compound?
The empirical formula is representative for the chemical composition of a compound; the structural formula is representative for the spatial structure of the compound.
The empirical formula for cumene a compound containing only carbon and hydrogen is C3H4. Its Molecular mass is 120 g. What is the molecular formula for cumene?
This molecular formula is C9H12.
How do you know if a formula is an empirical formula?
An empirical formula has no data about the structure of a compound.
The combustion data for an unknown compound containing carbon hydrogen and oxygen was analyzed and the empirical formula for the unknown was found to be C3H4O The molar mass of the unknown was fou?
C6h12o3
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
What is a combustion analysis used for?
Combustion analysis is used in chemistry to determine the elementary form of a pure compound. This is done by using a form of heating the sample so the results can be properly analyzed.
If a compound containing chromium and silicon has 73.52 mass percent chromium what is its empirical formula?
To find the empirical formula, we need to determine the molar ratio of chromium to silicon. If 73.52% of the compound's mass is chromium, then the mass of silicon must be 100% - 73.52% = 26.48%. Next, we convert these percentages to moles, then divide by the smallest number of moles to get the simplest whole number ratio. The empirical formula is CrSi.
What is the empirical formula for 13 percent magnesium and 87 percent bromine?
The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.
What is nitrogen oxide containing 53.85 N acts as a vasodilator lowering blood pressure in the human body. What is its empirical formula?
The empirical formula of the nitrogen oxide containing 53.85% nitrogen is N2O. This compound is commonly known as nitrous oxide or laughing gas, and it can act as a vasodilator to lower blood pressure when administered in controlled amounts.
What is the empirical formula for a molecule containing 46.8 Si and 53.2 O?
The empirical formula would be SiO2. This is because the ratio of Si to O in the molecule is 1:2, which simplifies to SiO2.
Which could represent the empirical and the formula of a given compound?
The empirical formula is representative for the chemical composition of a compound; the structural formula is representative for the spatial structure of the compound.
The empirical formula for cumene a compound containing only carbon and hydrogen is C3H4. Its Molecular mass is 120 g. What is the molecular formula for cumene?
This molecular formula is C9H12.
How do you know if a formula is an empirical formula?
An empirical formula has no data about the structure of a compound.
What is the empirical formula of a compound that contains 53.73 percent Fe and 46.27 percent of S?
The empirical formula of the compound containing 53.73% Fe and 46.27% S is FeS. This is determined by dividing the given percentages by the molar mass of each element to find the mole ratio, which simplifies to FeS in this case.
The lowest whole number ratio of the elements in a compound is called the?
An empirical formula refers to the chemical formula that indicates the simplest ratio of atoms in a compound. Two different compounds may have the same empirical formula.
