That is a molecular formula.
I can't off the top of my head think of any compound with that molecular formula, though. It's not methoxyethane or a propanol, because it's got one too few hydrogen atoms. It's not propanone or cyclopropanol or oxetane or a propenol, because it's got one too many hydrogen atoms.
The molecular formula of ethanol is C2H4O. This shows that each molecule of ethanol contains two carbon atoms.
C2H4O is the molecular formula for an organic compound known as ethanol or ethylene oxide, depending on its arrangement. It consists of carbon, hydrogen, and oxygen, which are characteristic elements found in organic compounds. Therefore, C2H4O is classified as an organic compound.
The chemical formula of polyvinyl alcohol (PVA) is (C2H4O)n, where n represents the number of repeating ethylene (C2H4O) units in the polymer chain.
Ethanol, or drinking alcohol, is a solvent and reagent with the chemical formula CH3CH2OH.Ethanal, better known as acetaldehyde, is an aldehyde with the formula CH3CHO.
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
The molecular formula of ethanol is C2H4O. This shows that each molecule of ethanol contains two carbon atoms.
The formula that represents an aldehyde is c) C2H4O. Aldehydes have the general formula RCHO, where R is an alkyl or aryl group.
To calculate the gram molecular weight of an unknown liquid, you need to determine the molecular formula of the liquid and then add up the atomic weights of all the atoms in the formula. This will give you the gram molecular weight of the unknown liquid.
The chemical formula of polyvinyl alcohol (PVA) is (C2H4O)n, where n represents the number of repeating ethylene (C2H4O) units in the polymer chain.
Ethanol, or drinking alcohol, is a solvent and reagent with the chemical formula CH3CH2OH.Ethanal, better known as acetaldehyde, is an aldehyde with the formula CH3CHO.
The formula for an aldehyde is c) C2H4O. Aldehydes have the functional group -CHO, and this formula fits that description.
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
The chemical formula of ethanal (acetic aldehyde) is CH3CHO.
The empirical formula is CH2O. To find the molecular formula, you need to calculate the empirical formula weight (30 g/mol) and divide the molecular mass (180.0 g/mol) by the empirical formula weight to get 6. This means the molecular formula is (CH2O)6, which simplifies to C6H12O6, the molecular formula of glucose.
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
To determine the molecular formula from the empirical formula CH2O and given molecular mass of 60.0 amu, calculate the empirical formula mass: (12.01 g/mol for C) + 2(1.01 g/mol for H) + 16.00 g/mol for O = 30.02 g/mol. Then divide the given molecular mass by the empirical formula mass to find the factor by which the empirical formula must be multiplied to get the molecular formula: 60.0 amu / 30.02 g/mol ≈ 2. Next, multiply the subscripts in the empirical formula by this factor to find the molecular formula: 2(C)2(H)2(O) = C4H4O2, giving the molecular formula as C4H4O2.