0
What is the molecular formula of a compound that has a molecular mass of 54 and the empirical formula C2H3?
Wiki User
∙ 11y ago
C4H6. C2H3 gives a molecular mass of 27, 54/27 gives 2. Therefore the molecular formula is twice the empirical formula.
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
What is the molecular formula of a compound given the molar mass of the compound is 162.27 grams and the empirical formula is C2H3?
The empirical mass is C2H3 2 x 12 = 24 3 x 1 = 3 24 + 3 = 27 So divide 27 into 166.01 Hence 162.27 / 27 = 6.01 ~ 6 So multiply each atom in the empirical formula by '6' Hence Empirical C2H3 Molecular C12H18
What is the empirical formula for C8H10?
Emperical formula FOR C8H12 is C2H3
What is the empirical formula of C4H6?
The empirical formula of organic compounds is the lowest whole number ratio of atoms contained in the substance, as defined in chemistry. The empirical formula gives the minimal ratio of the number of various atoms that exist. It's an empirical formula, if the formula is shortened, but not the exact number of atoms in the molecule, C4H6 is the chemical formula for butane. For every mole of carbon, there are two moles of hydrogen. The carbon-to-hydrogen ratio equals 2:3. C2H3 is the empirical formula for butane (C4H6). Hence, the correct answer is C2H3.
What is the compound C2H3?
dicarbon trihydrogen
What is the name for C2H3?
soot
What is the chemical formula of polyvinyl acetate?
{CH2- CH-OOC-CH3}N where N is very large and often over 200,000 CH2=CH-OOC-CH3 is the formual for vinyl acetate monomer. The double bond opens up and polymerizes giving the structure above with only a single bond between the CH2 and the CH.
