The empirical mass is C2H3 2 x 12 = 24 3 x 1 = 3 24 + 3 = 27 So divide 27 into 166.01 Hence 162.27 / 27 = 6.01 ~ 6 So multiply each atom in the empirical formula by '6' Hence Empirical C2H3 Molecular C12H18
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mixture
An ionic compound is an example of a chemical compound.
plastic is a compound .
C4H6. C2H3 gives a molecular mass of 27, 54/27 gives 2. Therefore the molecular formula is twice the empirical formula.
The empirical mass is C2H3 2 x 12 = 24 3 x 1 = 3 24 + 3 = 27 So divide 27 into 166.01 Hence 162.27 / 27 = 6.01 ~ 6 So multiply each atom in the empirical formula by '6' Hence Empirical C2H3 Molecular C12H18
soot
Emperical formula FOR C8H12 is C2H3
The empirical formula of organic compounds is the lowest whole number ratio of atoms contained in the substance, as defined in chemistry. The empirical formula gives the minimal ratio of the number of various atoms that exist. It's an empirical formula, if the formula is shortened, but not the exact number of atoms in the molecule, C4H6 is the chemical formula for butane. For every mole of carbon, there are two moles of hydrogen. The carbon-to-hydrogen ratio equals 2:3. C2H3 is the empirical formula for butane (C4H6). Hence, the correct answer is C2H3.
It is a compound.
mixture
An ionic compound is an example of a chemical compound.
plastic is a compound .
It is a compound.
Water is a compound
soap is a compound