There are many compounds with a relative mass of 72.
Eg. pentane (C5H12), methyl butane (CH3)-(C4H9), dimethyl propane (CH3)2-(C3H6). Inorganic formula's can not easily be guessed, but undoubtly be found.
Only one (isotope of an) element has the relative mass of 72: Gallium, (Ga-72), but this is not a natural, stable isotope. Gallium has not a molecular formula (being a metal like aluminum) only an atomic symbol: Ga.
The molecular mass of C2H6 is 30.07 g/mole
Pentane has the molecular structure C5H12 So multiply the number of each atom with its molecular mass. (see the periodic table) 5*12 + 12*1 = 72 gram per mole. Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole
The atomic mass is 72
* Percentage mass = atomic mass of required element/ total mass of compound. * Glucose is represented by the formula C6H12O6. The relative molecular mass (Mr)= (6 x 12) + (12 x 1) + (6 x 16) = 180. # Let's start with carbon: one atom of carbon has an atomic mass of 12, but there are 6 atoms of carbon in an molecule of glucose. 6 x 12 = 72. Divide this by 180 and multiply by 100 to give 40%. # Next, we have hydrogen. Each atom has an atomic mass of 1. Multiply by 12 to give 12. Then divide by 180 and multiply by 100, to give 6.6% # Finally, there's oxygen. One atom of oxygen has an atomic mass of 16, so multiply 16 by 6, which gives 96. Divide this by 180, then multiply by 100 to give 53.3%. * To check that these % masses are correct, add the percentages to ensure they make 100: 40 + 6.6 + 53.3 = 99.9%, which is close enough!
Sucrose: C12H22O11Formula Weight: 342.3Carbon: 12 * 12.01 g/mol = 144.12144.12/342.3 = 42.10% CarbonYou can always check the other elements to double check:Hydrogen: 22*1 = 2222/342.3 = 6.4% HydrogenOxygen: 11*16.01 = 176.11176.11/342.3 = 51.44% Oxygen
Molecular mass of pentane is 72 u.
The molecular mass of C2H6 is 30.07 g/mole
Pentane has the molecular structure C5H12 So multiply the number of each atom with its molecular mass. (see the periodic table) 5*12 + 12*1 = 72 gram per mole. Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole
Percent composition means finding the total mass of each element in a molecule and then dividing it by the molecular mass. Use the molecular formula to help you find out how many atoms of each element you'll need. For carbon: 6 C x 12 g = 72 g For hydrogen: 10 H x 1 g = 10 g For oxygen: 5 O x 16 g = 80 g Molecular mass = C + H + O = 72 + 10 + 80 = 162 g Percent composition of C = 72/162 = 0.4444 = about 44.45% Percent composition of H = 10/162 = 0.061728395 = about 6.17% Percent composition of O = 80/162 = 0.49382716 = about 49.38%
72
Vinegar itself is a mixture of water and acetic acid. water is H2O Acetic acid is HC2H3O2
The atomic mass is 72
* Percentage mass = atomic mass of required element/ total mass of compound. * Glucose is represented by the formula C6H12O6. The relative molecular mass (Mr)= (6 x 12) + (12 x 1) + (6 x 16) = 180. # Let's start with carbon: one atom of carbon has an atomic mass of 12, but there are 6 atoms of carbon in an molecule of glucose. 6 x 12 = 72. Divide this by 180 and multiply by 100 to give 40%. # Next, we have hydrogen. Each atom has an atomic mass of 1. Multiply by 12 to give 12. Then divide by 180 and multiply by 100, to give 6.6% # Finally, there's oxygen. One atom of oxygen has an atomic mass of 16, so multiply 16 by 6, which gives 96. Divide this by 180, then multiply by 100 to give 53.3%. * To check that these % masses are correct, add the percentages to ensure they make 100: 40 + 6.6 + 53.3 = 99.9%, which is close enough!
Remember the general moles equation. moles = mass(g) / Mr NB 'Mr' means the relative molecular mass. The Mr for LiOH can be calculated from the Periodic Table using Atomic masses. Atomic mass (Li = 7 ) Atomic mass (O = 16) Atomic mass (H = 1) Add 7 + 16 + 1 = 24 (The Mr of LiOH) Substituting in to the moles eq'n 3 = mass(g) / 24 Algebraically rearrange mass(g) = 3 x 24 mass = 72 g
72 kilograms is 158 pounds and 11.72 ounces.
chromium
Germanium is a metal element. Atomic mass of it is 72.