C6H12O6 is the molecular formula for sugar (glucose).
Molecular mass/ molecular weight = (Number of C atoms) (Atomic weight of C) +
(Number of H atoms) (Atomic weight of H) +
(Number of O atoms) (Atomic weight of O) = (6) (12) + 12 (1) + 6 (16) = 180 (g/mole)
To find the number of moles in 15.8 grams of C6H12O6, first calculate the molar mass of C6H12O6 which is 180 g/mol (126 + 112 + 16*6). Then divide the given mass by the molar mass to get the number of moles. In this case, 15.8g / 180 g/mol = 0.088 moles.
The molar mass of fructose (C6H12O6) is approximately 180.16 g/mol.
To find the mass of 1.64x10^23 molecules of C6H12O6, you need to determine the molar mass of one molecule of C6H12O6. Then, use Avogadro's number (6.022x10^23 molecules/mol) to convert the number of molecules to moles. Finally, multiply the number of moles by the molar mass to get the mass in grams.
First find the molar mass... C -- 6 x 12 = 72 O -- 6 x 16 = 96 H -- 12 x 1 = 12, now add all -- 72 + 96 + 12 = 180 g/mole multiply 0.699 x 180 = 125.82 g --- Round to 126 g
The molar mass of sulfur is approximately 32.06 grams/mol. Therefore, 1 mol of sulfur atoms will have a mass of 32.06 grams.
To calculate the mole fraction of glucose, first find the moles of each component by dividing its mass by its molar mass. The molar mass of glucose (C6H12O6) is 180 g/mol. The moles of glucose is 180g / 180 g/mol = 1 mol. The moles of water is 162g / 18 g/mol = 9 mol. The total moles in the solution is 1 + 9 = 10 mol. The mole fraction of glucose is 1 mol / 10 mol = 0.1.
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
To find the number of moles in 15.8 grams of C6H12O6, first calculate the molar mass of C6H12O6 which is 180 g/mol (126 + 112 + 16*6). Then divide the given mass by the molar mass to get the number of moles. In this case, 15.8g / 180 g/mol = 0.088 moles.
The formula mass of C6H12O6 (glucose) is calculated by summing the atomic masses of the elements in the compound. The atomic masses of carbon (C) is 12.01, hydrogen (H) is 1.01, and oxygen (O) is 16.00. Hence, the formula mass of C6H12O6 is (6 * 12.01) + (12 * 1.01) + (6 * 16.00) = 180.16 g/mol.
The molar mass of fructose (C6H12O6) is approximately 180.16 g/mol.
To find the mass of 1.64x10^23 molecules of C6H12O6, you need to determine the molar mass of one molecule of C6H12O6. Then, use Avogadro's number (6.022x10^23 molecules/mol) to convert the number of molecules to moles. Finally, multiply the number of moles by the molar mass to get the mass in grams.
First find the molar mass... C -- 6 x 12 = 72 O -- 6 x 16 = 96 H -- 12 x 1 = 12, now add all -- 72 + 96 + 12 = 180 g/mole multiply 0.699 x 180 = 125.82 g --- Round to 126 g
0.260 mole C6H12O6 (6.022 X 10^23/1 mole C6H12O6) = 1.57 X 10^23 atoms of glucose
The empirical formula CH2O has a molar mass of 30 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, which is a multiple of the empirical formula, you divide the molar mass given (180 g/mol) by the empirical formula mass (30 g/mol), giving you 6. Therefore, the molecular formula for the compound is (CH2O)6, which simplifies to C6H12O6, the molecular formula for glucose.
.292 mol
To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.
According to the periodic table, the atomic mass of rubidium, Rb is 85.5. This is numerically equal to the molar mass in g/mol. Therefore the mass of 1 mol of Rb is 85.5g.Mass of 1 mol means the molar mass of the element. Molar mass of Rubidium is 85.47 gmol-1. Rb is in the 1st group.