answersLogoWhite

0

The mass is 49,06 g.

User Avatar

Wiki User

7y ago

What else can I help you with?

Continue Learning about Chemistry

How many moles are contained in 15.8 grams of C6H12O6?

To find the number of moles in 15.8 grams of C6H12O6, first calculate the molar mass of C6H12O6 which is 180 g/mol (126 + 112 + 16*6). Then divide the given mass by the molar mass to get the number of moles. In this case, 15.8g / 180 g/mol = 0.088 moles.


How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?

To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.


What is the mass in grams of 1.20x1025 molecules of ammonia NH3?

To find the mass in grams of 1.20x10^25 molecules of ammonia (NH3), you first calculate the molar mass of NH3 (17.031 g/mol). Then, divide the given number of molecules by Avogadro's number (6.022x10^23 molecules/mol) to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams, which will be approximately 4.08x10^2 grams.


What is the mass in grams of 7.50 and times1020 molecules of caffeine C8H10N4O2?

To calculate the mass in grams of 7.50 x 10^20 molecules of caffeine (C8H10N4O2), you need to determine the molar mass of caffeine and then convert the number of molecules to moles using Avogadro's number. Finally, multiply the moles of caffeine by the molar mass to find the mass in grams.


What is the mass of 1 mol of C6H12O6?

C6H12O6 is the molecular formula for sugar (glucose).Molecular mass/ molecular weight = (Number of C atoms) (Atomic weight of C) +(Number of H atoms) (Atomic weight of H) +(Number of O atoms) (Atomic weight of O) = (6) (12) + 12 (1) + 6 (16) = 180 (g/mole)

Related Questions

How many molecules are in 720 grams of C6H12O6?

To determine the number of molecules in 720 grams of C6H12O6 (glucose), you first need to calculate the number of moles present. The molar mass of glucose is 180.16 g/mol. Dividing 720 grams by the molar mass gives you 4 moles of C6H12O6. One mole of any substance contains Avogadro's number of molecules, which is approximately 6.022 x 10^23. Therefore, 4 moles of C6H12O6 would contain about 2.409 x 10^24 molecules.


What mass of oxygen in grams is in 147.2 grams of glucose?

To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.


How many moles are contained in 15.8 grams of C6H12O6?

To find the number of moles in 15.8 grams of C6H12O6, first calculate the molar mass of C6H12O6 which is 180 g/mol (126 + 112 + 16*6). Then divide the given mass by the molar mass to get the number of moles. In this case, 15.8g / 180 g/mol = 0.088 moles.


How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?

To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.


What is the molarity of an aqueous solution containing 32.8 g of C6H12O6 in 1.0 L of solution?

Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6


What is the mass in grams of 1.20x1025 molecules of ammonia NH3?

To find the mass in grams of 1.20x10^25 molecules of ammonia (NH3), you first calculate the molar mass of NH3 (17.031 g/mol). Then, divide the given number of molecules by Avogadro's number (6.022x10^23 molecules/mol) to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams, which will be approximately 4.08x10^2 grams.


What is the mass in grams of 7.50 and times1020 molecules of caffeine C8H10N4O2?

To calculate the mass in grams of 7.50 x 10^20 molecules of caffeine (C8H10N4O2), you need to determine the molar mass of caffeine and then convert the number of molecules to moles using Avogadro's number. Finally, multiply the moles of caffeine by the molar mass to find the mass in grams.


How many grams are in 4.1 X 1022 molecules of N2I6?

To calculate the number of grams in 4.1 x 10^22 molecules of N2I6, you first need to find the molar mass of N2I6. Then, use this molar mass to convert the number of molecules to grams using Avogadro's number and the formula: grams = (number of molecules) / (Avogadro's number) * molar mass.


What is the mass (in grams) of methanol of 9.09x1024 molecules of methanol?

The mass is 483,62 g.


What is the mass of 1 mol of C6H12O6?

C6H12O6 is the molecular formula for sugar (glucose).Molecular mass/ molecular weight = (Number of C atoms) (Atomic weight of C) +(Number of H atoms) (Atomic weight of H) +(Number of O atoms) (Atomic weight of O) = (6) (12) + 12 (1) + 6 (16) = 180 (g/mole)


What is the mass(in grams) of 9.401024 molecules of methanol?

The answer is 50,196 g.


How many grams are in 8.2 x 10 to the 22 molecules of N2I6?

To convert molecules to grams, you need to use the molar mass of the compound. For N2I6, the molar mass is 539.59 g/mol. First, calculate the number of moles in 8.2 x 10^22 molecules by dividing the number of molecules by Avogadro's number. Then, multiply the number of moles by the molar mass to find the grams.