You need to know the mass. The equation for momentum (p) is p = mv, where m is the mass in kg and v is the velocity in m/s.
momentum change = 670.56 kilogram-meter/second
momentum=mass*velocity 1*10=10Ns
Since momentum is mass x velocity, the vehicle with the greater mass would have more momentum in this case.
Yes, all things being equal, crash severity does increase proportional to the speed of each vehicle at impact, and is a vector sum. So, there is a big difference between crash severity at impact from being "rear-ended" (when one vehicle is traveling the same direction as another, and impacts the front of their vehicle with the rear of another) and a "head-on" impact (two cars traveling into one another, impacting both front bumpers). In the rear-end impact, you take the momentum (mass times velocity) of the rear, impacting vehicle "A" and subtract the momentum of the front-most impacted vehicle "B", and that gives you the resultant impact force (the difference in momentum being transferred). weak impact scenario example: vehicle A is traveling 60 mph, and vehicle B is the same mass and is traveling 50 mph. The difference in momentum would be the mass times 10 mph...not much. severe impact scenario: vehicle A is traveling 70 mph, and vehicle B is at rest (0 mph)...large impact. In the head-on impact, you have the most severe crash scenario. In this case, you ADD the momentum of vehicle A with the momentum of vehicle B, and you get the resultant force of impact. Even if both vehicles are traveling 30 mph, with the same mass, and have a heaad-on collision, the is close to the same as one vehicle traveling 10 mph and hitting the other vehicle going 70 mph...severe impact.
To find the momentum of an object you must know the mass of the object and the velocity at which it travels. Example: A 50kg man runs at 10m/s. What is his momentum? Momentum = Mass x Velocity 50 x 10 = 500 kgm/s
momentum change = 670.56 kilogram-meter/second
Up to about 10 MPH, if fully charged. Because of gravity, the momentum you create lets you go faster, given you are going downhill. Uphill the highest speed the motor will go is 10 mph, and that is only if it is fully charged.
A bowling ball has more momentum. You cannot throw it as fast, but a tenpin ball weighs 16 pounds and a baseball only 1/3 pound. Momentum is mass times velocity and if you throw the bowling ball at 10 mph but the baseball at 90 mph the bowling ball still has much more momentum.
Yes. momentum is figured out by the formula p =mv momentum = mass (weight) x velocity The train would have a massive amount of mass and as you can see in the formula the car (mass) would not be anywhere close to the momentum of the train.
Momentum = Mass x Velocity. They could have the same momentum if the motorcycle is going fast and the van is going slow. If the van weighs ten times as much as the motorcycle, and is driving 5 mph it would have the same momentum as the motorcycle driving 50 mph.
momentum
momentum=mass*velocity 1*10=10Ns
Since momentum is mass x velocity, the vehicle with the greater mass would have more momentum in this case.
Momentum = Mass x Velocity (p=mv)Of course an object at rest would have no momentum no matter what the mass is (velocity = 0 so momentum = 0).Playing volleyball with a balloon might be something that would be considered low momentum. You can hit it as hard as you like, but it has so little mass that its momentum can hardly overcome the air resistance.You might push a small car at, say 1/4 MPH, and it would have relatively little momentum.However a train traveling at the same 1/4 MPH would still have a lot of momentum.
Momentum Deferred was created on 2009-10-08.
Yes, all things being equal, crash severity does increase proportional to the speed of each vehicle at impact, and is a vector sum. So, there is a big difference between crash severity at impact from being "rear-ended" (when one vehicle is traveling the same direction as another, and impacts the front of their vehicle with the rear of another) and a "head-on" impact (two cars traveling into one another, impacting both front bumpers). In the rear-end impact, you take the momentum (mass times velocity) of the rear, impacting vehicle "A" and subtract the momentum of the front-most impacted vehicle "B", and that gives you the resultant impact force (the difference in momentum being transferred). weak impact scenario example: vehicle A is traveling 60 mph, and vehicle B is the same mass and is traveling 50 mph. The difference in momentum would be the mass times 10 mph...not much. severe impact scenario: vehicle A is traveling 70 mph, and vehicle B is at rest (0 mph)...large impact. In the head-on impact, you have the most severe crash scenario. In this case, you ADD the momentum of vehicle A with the momentum of vehicle B, and you get the resultant force of impact. Even if both vehicles are traveling 30 mph, with the same mass, and have a heaad-on collision, the is close to the same as one vehicle traveling 10 mph and hitting the other vehicle going 70 mph...severe impact.
Yes, all things being equal, crash severity does increase proportional to the speed of each vehicle at impact, and is a vector sum. So, there is a big difference between crash severity at impact from being "rear-ended" (when one vehicle is traveling the same direction as another, and impacts the front of their vehicle with the rear of another) and a "head-on" impact (two cars traveling into one another, impacting both front bumpers). In the rear-end impact, you take the momentum (mass times velocity) of the rear, impacting vehicle "A" and subtract the momentum of the front-most impacted vehicle "B", and that gives you the resultant impact force (the difference in momentum being transferred). weak impact scenario example: vehicle A is traveling 60 mph, and vehicle B is the same mass and is traveling 50 mph. The difference in momentum would be the mass times 10 mph...not much. severe impact scenario: vehicle A is traveling 70 mph, and vehicle B is at rest (0 mph)...large impact. In the head-on impact, you have the most severe crash scenario. In this case, you ADD the momentum of vehicle A with the momentum of vehicle B, and you get the resultant force of impact. Even if both vehicles are traveling 30 mph, with the same mass, and have a heaad-on collision, the is close to the same as one vehicle traveling 10 mph and hitting the other vehicle going 70 mph...severe impact.