The chemical name for Zn3(PO4)2 is zinc phosphate.
To find the percent composition of phosphorus in Zn3(PO4)2, calculate the molar mass of the entire compound first. The molar mass of Zn3(PO4)2 is 386.06 g/mol. Then, determine the molar mass of phosphorus in the compound, which is 283.89 g/mol. Finally, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage. In this case, the percent composition of phosphorus in Zn3(PO4)2 is approximately 73.65%.
To my knowledge, it is 7 x Zinc Phosphate and carries a charge of positive 2. Hope this helps :)
The net ionic equation for the reaction between zinc bromide (ZnBr2) and sodium phosphate (Na3PO4) to produce a precipitate of zinc phosphate (Zn3(PO4)2) is: 3Zn^2+ + 2PO4^3- -> Zn3(PO4)2 Since all the ions are participating in the reaction, there is no spectator ion to cancel out in this net ionic equation.
Zn3(PO4)2 is an ionic compound. This is because Zn is a metal and PO4 is a polyatomic ion, resulting in the transfer of electrons from Zn to the PO4 ion to form the ionic bond.
Zinc (II) = Zn+2Hydroxide = OH-So Zinc Hydroxide = Zn(OH)2Hydrogen =H+ Phosphate = PO4-3So Hydrogen Phosphate = H3PO4So Zn(OH)2 + H3PO4 ---> Zn3(PO4)2 + H2O is the initial equation, but you need to balance it before you can do anything with it, that means that you need an equal amount of each element on each side of the equation.3 Zn(OH)2 + 2 H3PO4 ---> Zn3(PO4)2 + 6H2OIts easy to check the equation to make sure its balanced, just count your elements on each side of the arrow3Zn + 12H + 6O + 2PO4 on each side of the equation, and its balanced.
The chemical name for Zn3(PO4)2 is zinc phosphate.
The name of this compound is zinc phosphide.
To find the percent composition of phosphorus in Zn3(PO4)2, calculate the molar mass of PO4 (phosphate) first. The molar mass of PO4 is 1 * P (phosphorus) + 4 * O (oxygen). Then, divide the molar mass of P by the molar mass of the entire Zn3(PO4)2 compound and multiply by 100 to get the percentage.
1 mole Zn3(PO4)2 (2 moles P/1 mole Zn3(PO4)2) 2 moles phosphorous ===============
1 mole of the antiperspirant ingredient Zn3(PO4)2 contain 2 moles of phpsphorus.
To find the percent composition of phosphorus in Zn3(PO4)2, calculate the molar mass of the entire compound first. The molar mass of Zn3(PO4)2 is 386.06 g/mol. Then, determine the molar mass of phosphorus in the compound, which is 283.89 g/mol. Finally, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage. In this case, the percent composition of phosphorus in Zn3(PO4)2 is approximately 73.65%.
Zinc Phosphate.=)
To my knowledge, it is 7 x Zinc Phosphate and carries a charge of positive 2. Hope this helps :)
Zn3(PO4)2Zn3(PO4)2
To determine the chemical formula for zinc phosphate, first identify the charges of the ions involved. Zinc typically has a +2 charge (Zn²⁺) and phosphate has a -3 charge (PO₄³⁻). To balance the charges, you need three zinc ions (3 x 2 = 6+) for every two phosphate ions (2 x 3 = 6-), giving you the formula Zn₃(PO₄)₂.
The net ionic equation for the reaction between zinc bromide (ZnBr2) and sodium phosphate (Na3PO4) to produce a precipitate of zinc phosphate (Zn3(PO4)2) is: 3Zn^2+ + 2PO4^3- -> Zn3(PO4)2 Since all the ions are participating in the reaction, there is no spectator ion to cancel out in this net ionic equation.
phosphoric acid H3PO4 sodium hydroxide NaOH H3PO4 + 3NaOH = Na3PO4 + 3H2O 1 acid + 3 base = 1 salt + 3 water