3Zn2+(aq)+2PO43-(aq) ----> Zn3(PO4)2(S)
When silver nitrate is added to a solution containing bromide ions, a white precipitate of silver bromide will form. This is due to a chemical reaction between the silver nitrate and bromide ions, resulting in the insoluble silver bromide precipitate.
When aqueous bromide and aqueous silver nitrate mix, a white precipitate of silver bromide is formed. This is a chemical reaction that involves the exchange of ions: Ag⁺ + Br⁻ → AgBr↓.
When chloride and bromide ions are mixed with silver nitrate, a white precipitate of silver chloride and a pale yellow precipitate of silver bromide are formed. This reaction is a qualitative test to distinguish between chloride, bromide, and nitrate ions.
Silver bromide and sodium nitrate will react to form silver nitrate and sodium bromide as the products. The precipitate formed will be silver bromide, which is insoluble in water and will appear as a white solid in the reaction mixture.
The symbol equation for the reaction between chlorine and sodium bromide is: Cl2 + 2NaBr → 2NaCl + Br2.
This equation is:AgNO3 + KBr = AgBr(s) + KNO3Silver bromide is a white precipitate.
When copper(II) bromide reacts with sodium phosphate, a double displacement reaction occurs, resulting in the formation of copper(II) phosphate and sodium bromide. The balanced chemical equation for this reaction is: 3 CuBr₂ + 2 Na₃PO₄ → Cu₃(PO₄)₂ + 6 NaBr. The copper(II) phosphate may precipitate out of solution depending on the concentrations of the reactants. This reaction illustrates the exchange of ions between the two compounds.
The precipitate formed when potassium bromide and silver nitrate are mixed is silver bromide (AgBr), which is a white solid. This reaction is a double displacement reaction where the silver ions from silver nitrate exchange with the bromide ions from potassium bromide to form the insoluble silver bromide.
When silver nitrate is added to a solution containing bromide ions, a white precipitate of silver bromide will form. This is due to a chemical reaction between the silver nitrate and bromide ions, resulting in the insoluble silver bromide precipitate.
Yes, Nibr2 and AgNO3 will form a precipitate when mixed. This reaction is a double displacement reaction where the insoluble silver bromide (AgBr) precipitate will form in solution.
The reaction is:AgNO3 + KBr = AgBr = KNO3Silver bromide is a precipitate.
When aqueous bromide and aqueous silver nitrate mix, a white precipitate of silver bromide is formed. This is a chemical reaction that involves the exchange of ions: Ag⁺ + Br⁻ → AgBr↓.
When chloride and bromide ions are mixed with silver nitrate, a white precipitate of silver chloride and a pale yellow precipitate of silver bromide are formed. This reaction is a qualitative test to distinguish between chloride, bromide, and nitrate ions.
When silver nitrate and sodium bromide are mixed together in a laboratory setting, a white precipitate of silver bromide is formed. This reaction is a double displacement reaction where the silver ions from silver nitrate combine with the bromide ions from sodium bromide to form an insoluble compound. The formation of the precipitate indicates that a chemical reaction has occurred.
The chemical reaction between silver nitrate and bromine results in the formation of silver bromide and nitric acid. The balanced chemical equation for this reaction is 2AgNO3 + Br2 -> 2AgBr + 2 HNO3. Silver bromide is a yellowish solid precipitate, and nitric acid is a byproduct of the reaction.
When aqueous bromide and aqueous silver nitrate are mixed, a white precipitate of silver bromide is formed due to a double displacement reaction. The balanced chemical equation for this reaction is: AgNO3(aq) + KBr(aq) → AgBr(s) + KNO3(aq)
The reaction between CH3CH2MgBr (ethylmagnesium bromide) and methanol results in the formation of ethanol and magnesium bromide. The balanced equation for this reaction is: CH3CH2MgBr + CH3OH -> CH3CH2OH + MgBr2