This equation is:
AgNO3 + KBr = AgBr(s) + KNO3
Silver bromide is a white precipitate.
The balanced chemical equation for the reaction where potassium (K) replaces magnesium (Mg) in magnesium bromide (MgBr2) to form potassium bromide (KBr) and magnesium (Mg) is: [ 2K + MgBr_2 \rightarrow 2KBr + Mg ] This equation indicates that two moles of potassium react with one mole of magnesium bromide to produce two moles of potassium bromide and one mole of magnesium.
The balanced equation for the reaction between manganese(II) bromide and sodium hydroxide is: MnBr2 + 2NaOH → Mn(OH)2 + 2NaBr.
The reaction is:AgNO3 + KBr = AgBr = KNO3Silver bromide is a precipitate.
This looks very much like the first part of a chemical equation: the description of the process of a chemical reaction. The conventional rules for chemical equations are that - just like mathematical/algebraic equations - the two sides must match. KBr is Potassium Bromide; I2 is iodine, which in its natural state consists of two atoms joined together, and so is written with the subscript '2'. As one molecule of iodine has two atoms, two molecules of potassium bromide must be placed in the equation to make the sides match. If these two substances are made to react (to my recollection, since bromine is more reactive than iodine this reaction would not occur unless catalyzed in some way, say by heat) then the iodine and bromide would change places, leaving potassium iodide and bromine (a brown, very pongy gas at room temperature); so the whole equation would be: 2 KBr + I2 -> 2 KI + Br2
Any reaction occur.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
KBr + H2O = Kaq+ Braq- Haq+ OHaq-
2 KBr + BaI2 ----> 2 KI + BaBr2
The reaction of potassium bromide with chlorine is known as a displacement reaction, where the more reactive chlorine displaces the less reactive bromide to form potassium chloride and elemental bromine.
Dibromide ions and KCl http://jchemed.chem.wisc.edu/jcesoft/cca/cca3/MAIN/CLKBR/PAGE1.HTM
When fluorine reacts with potassium bromide, the fluorine displaces bromine from the compound to form potassium fluoride and bromine gas. This is a redox reaction where fluorine is reduced and bromine is oxidized.
The balanced chemical equation for this reaction is: 2KBr + Al(NO3)3 → 2KNO3 + AlBr3
The balanced equation for potassium bromide (KBr) and hydrochloric acid (HCl) reacting is: KBr + HCl → KCl + HBr. This reaction is a double displacement reaction, where potassium chloride (KCl) and hydrobromic acid (HBr) are formed.
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
The compound made in the reaction between bromine and potassium is potassium bromide (KBr). Bromine reacts with potassium to form a white crystalline solid compound.