This looks very much like the first part of a chemical equation: the description of the process of a chemical reaction. The conventional rules for chemical equations are that - just like mathematical/algebraic equations - the two sides must match. KBr is Potassium Bromide; I2 is iodine, which in its natural state consists of two atoms joined together, and so is written with the subscript '2'. As one molecule of iodine has two atoms, two molecules of potassium bromide must be placed in the equation to make the sides match.
If these two substances are made to react (to my recollection, since bromine is more reactive than iodine this reaction would not occur unless catalyzed in some way, say by heat) then the iodine and bromide would change places, leaving potassium iodide and bromine (a brown, very pongy gas at room temperature); so the whole equation would be:
2 KBr + I2 -> 2 KI + Br2
The reaction 2KBr → 2K + Br2 is endothermic because heat must be supplied to break the bonds in potassium bromide (KBr) in order to form potassium (K) and bromine gas (Br2).
The reaction represented by 2K + I2 is a combination or synthesis reaction, where potassium (K) and iodine (I2) combine to form potassium iodide (KI).
Bromine is the oxidizing element.
Yes, the reaction of hydrogen gas (H2) with iodine gas (I2) to produce hydrogen iodide gas (2HI) is a combination reaction. In this reaction, two elements (hydrogen and iodine) combine to form a single compound (hydrogen iodide).
When sodium metal is combined with iodine gas, an oxidation-reduction reaction occurs. Sodium loses and electron to form the sodium cation, and iodide gains an electron to form iodide. The resulting compound is NaI.
The balanced equation is: Br2 + 2Kl -> 2KBr + I2. This means there is a 2 in front of the underlined substance, KI.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
The equation 2K + Br2 -> 2KBr is balanced as there are equal numbers of atoms of each element on both sides of the reaction.
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
(4 ± i2) where i2 = -1
A) 2KI + BR2 --> KBR + I2 B) PCl3 + Cl2 --> PCl5 C) C5H12 + 8O2 --> 5CO2 + 6H2O D) Zn + 2HBr --> ZnBr2 + H2 =D
The equation for the reaction of potassium bromide with aqueous iodine is: 2KBr (aq) + I2 (aq) → 2KI (aq) + Br2 (aq) This reaction demonstrates a redox reaction where bromide ions are oxidized to bromine, and iodine is reduced to iodide.
well i don't really know the word chemical equation, but the balanced form is:2KI(aq) + Br(aq) --> I2(s) + 2KBr(aq)so if you just figure out the word form of the elements in the equation you'll figure it out..
2KI + Cl2 = 2KCl + I2
4