KBr + I2(aq) --> KBr + I2(aq)
It does not react because bromine is more electronegative and reactive than iodine.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
2KI + Cl2 = 2KCl + I2
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
because it is gay
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
2KI + Cl2 = 2KCl + I2
Potassium bromide has ionic bonding, and iodine bromide has covalent bonding.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
because it is gay
Yes, it is correct.
No. However, bromine would displace iodine in potassium iodide.
Bromine is more reactive than iodine/bromine is higher in the activity series than iodine
because it dosent
potassium iodide
2KI+Br2 ---->2KBr +I2