1 mole of the antiperspirant ingredient Zn3(PO4)2 contain 2 moles of phpsphorus.
it is 20456678
there are 0.675moles
To answer this you must first be given the mass of the sample or at least percentage and molecular formula that phosphorus is in
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
1.4 moles - the HCl is the limiting ingredient
1 mole Zn3(PO4)2 (2 moles P/1 mole Zn3(PO4)2) 2 moles phosphorous ===============
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
3,42 moles of phosphorus trichloride have 469,6686 g.
it is 20456678
4,70 moles of tetraphosphorus decaoxide contain 582,56 g phosphorus.
there are 0.675moles
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
8,75 moles of oxygen are needed.
To answer this you must first be given the mass of the sample or at least percentage and molecular formula that phosphorus is in
The number of phosphorus atoms is 63,181.10e23.
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
1.4 moles - the HCl is the limiting ingredient