The chemical name for V2O3 is Vandium Trioxide.
Vanadium (V) oxide
V= five the charge of V is +5 and it is a binary ionic compound thus the ide ending to the oxygen
The proper IUPAC name is "divanadium pentoxide", but the "di" prefix is often omitted.
Ionic compound V205 is vanadium(V) oxide.
V= Roman Numeral for 5
S203 2- is the Thiosulfate ion
aluminum oxide
Bismuth (III) Oxide(:
V2O3 is vanadium trioxide.
V2O5 is an ionic compound as the difference in electronegativities between oxygen and vanadium is above 1.7
What is the balanced molecular equation for the reaction of vanadium with molecular oxygen to form vanadium oxide?
the widely used catalyst is V2O5 .
The catalyst is vanadium(V) oxide (vanadium pentoxide, V2O5)
Theoretical YieldCalculate the theoretical yield when 1.54 × 103 g of V2O5 react with 1.96 × 103 g of Ca.First, we find the limiting reactant:1.54 × 103 g · 1 mol/181.881 g = 8.47 mol V2O51.96 × 103 g · 1 mol/40.078 g = 48.9 molThe number of moles of Ca to react completely with 8.47 mol V2O5 is 8.47 mol V2O5 · 5 mol Ca/1 mol V2O5 = 42.4 molSo Ca is in excess and we should use the molar amount of V2O5 to determine the theoretical yield of V.8.47 mol V2O5 · 2 mol V/1 mol V2O5 = 16.9 mol VPercent Yield What is the percent yield if 803 g of V are obtained?First, find out how many grams the theoretical yield of V represents: 16.9 mol · 50.941 g/mol = 863 gThen just divide the actual yield (given) by the theoretical yield: 803g/863g = 0.930 × 100% = 93.0%(notice how the units cancel out completely to give a unit-free ratio)Found this off a site.It does not use your numbers but if you're good, you can try to compare and contrast to find your answer.
V2O5 is an ionic compound as the difference in electronegativities between oxygen and vanadium is above 1.7
What is the balanced molecular equation for the reaction of vanadium with molecular oxygen to form vanadium oxide?
Formula: V2O5
Due to variable oxidation states of vanadium.
the widely used catalyst is V2O5 .
The catalyst is vanadium(V) oxide (vanadium pentoxide, V2O5)
Theoretical YieldCalculate the theoretical yield when 1.54 × 103 g of V2O5 react with 1.96 × 103 g of Ca.First, we find the limiting reactant:1.54 × 103 g · 1 mol/181.881 g = 8.47 mol V2O51.96 × 103 g · 1 mol/40.078 g = 48.9 molThe number of moles of Ca to react completely with 8.47 mol V2O5 is 8.47 mol V2O5 · 5 mol Ca/1 mol V2O5 = 42.4 molSo Ca is in excess and we should use the molar amount of V2O5 to determine the theoretical yield of V.8.47 mol V2O5 · 2 mol V/1 mol V2O5 = 16.9 mol VPercent Yield What is the percent yield if 803 g of V are obtained?First, find out how many grams the theoretical yield of V represents: 16.9 mol · 50.941 g/mol = 863 gThen just divide the actual yield (given) by the theoretical yield: 803g/863g = 0.930 × 100% = 93.0%(notice how the units cancel out completely to give a unit-free ratio)Found this off a site.It does not use your numbers but if you're good, you can try to compare and contrast to find your answer.
The reaction is:4 Fe + 3 O2= 2 Fe2O3
2KMnO4 + 5C2H2O4 + H2SO4 à 2MnSO4 + K2SO4 + 10CO2
Sulfur dioxide is converted to Sulfur trioxide using Oxygen and a oxidizing catalyst like Vanadium(V) oxide:SO2 + O2 --V2O5--> SO3
A vanadium pentoxide catalyst is used in order to speed up the reaction
the answer is +5. (V2O5) oxide has a charge of -2 and you just flip the numbers aroundd. [: