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What is the net ionic equation for 2AuCl3 aq 3Sn s --- 3SnCl2 aq 2Au s?
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What is the Merrill-Crowe process chemical equation?
2Au(CN) + Zn = 2Au + Zn(CN)4
What would happen if a piece of gold in a test tube of hydrchloric acid?
Probably nothing as gold is not very reactive. 2Au + 6HCl -> 2AuCl3 + 3H2 This hypothetical reaction with gold's normal 3 oxidation state would probably never be seen in nature.
What is the balanced equation for Au plus FeSo4?
One assumes this is a single displacement reaction. 2Au + FeSO4 --> Au2SO4 + Fe
A reaction between solid zinc and aqueous gold III nitrate?
3Zn(s) + 2Au(NO3)3(aq) ---- 3Zn(NO3)2(aq) + 2Au(s)
What happens when chlorine touches gold I know a chemical reaction occurs but how?
Well what chemically happens is an exchage of electrons. In an ionic bond, a metal (gold in this case) reacts with a non-metal (chlorine) to form an ionic compound. So Gold, or Au, most commonly has a charge of 3+. This means that normally to have a full outer shell of electrons, gold needs to give up three electrons, which is a loss of 3 negatives, which gives it a postivie charge. For chlorine to be 'happy' and have a full outer shell, it needs to gain one electron giving it a charge of 1-. These elements will only give up their electrons in specific situations and one is a bond. When chlorine gets put into an area with gold, then the chlorine takes an electron off of the gold, but since gold still needs to lose more electrons, then for every one gold atom losing electrons there must be 3 chlorine atoms taking them away. When this happens yu get a postively charged ion, Au+3 and three negatively charged ions, Cl-1. Since one of these ions is positive and the other negative, they act the same way as two different poles of a magnet would react. They attract to each other and stick together. Since they are now stuck together we know them as the compound AuCl3 or gold (III) chloride. (the III is a roman numeral for one, representing which type of gold was reacting) And that's whats happening when you put some solid gold into a chamber full of chlorine gas!Here is the chemical formula just in case you want to see it:2Au(s) + 3Cl2(g) --> 2AuCl3(s) Also if you are wondering, chlorine comes in pairs in its naturally occurring state, so we have to increase the number of gold around in order to properly react.
2Au plus aq plus Cu s 2Au s plus Cu2 plus aq?
2Au+(aq) + Cu(s) → 2Au(s) + Cu2+(aq)That formula is correct. It represents the net ionic equation of a complex oxidation-reduction reaction. Note that mass (2Au, 1Cu) and charge (2+) are preserved on both sides. The copper is oxidized from 0 to 2+, whereas the gold is reduced from 1+ to 0. This makes copper the reducing agent and gold the oxidizing agent.In layman's terms, when you put solid copper into a solution with gold in it, the gold will precipitate out. The reason the reaction happens at all is because gold is so resistant to being oxidized. Essentially any metal, including copper, will force gold out of solution.That equation, as stated above, is a net ionic equation and is the simplified form of a larger equation, such as:Molecular: 2AuNO3(aq) + Cu(s) → Cu(NO3)2(aq) + 2Au(s)Ionic: 2Au+(aq) + 2NO3-(aq) + Cu(s) → Cu2+(aq) + 2NO3-(aq) + 2Au(s)Note that the nitrate ions are the same on both sides and do not participate in the overall reaction, hence their removal to form the net ionic equation.
What is the Merrill-Crowe process chemical equation?
2Au(CN) + Zn = 2Au + Zn(CN)4
What would happen if a piece of gold in a test tube of hydrchloric acid?
Probably nothing as gold is not very reactive. 2Au + 6HCl -> 2AuCl3 + 3H2 This hypothetical reaction with gold's normal 3 oxidation state would probably never be seen in nature.
What is the balanced equation for Au plus FeSo4?
One assumes this is a single displacement reaction. 2Au + FeSO4 --> Au2SO4 + Fe
A reaction between solid zinc and aqueous gold III nitrate?
3Zn(s) + 2Au(NO3)3(aq) ---- 3Zn(NO3)2(aq) + 2Au(s)
How do you differentiate exp-ax2?
I'm not sure if you are asking about: e-ax2 or e-ax^2. Use the carets=^ in the future to raise something to a power.For e-ax2:You need to remember that: (ex)`= exalso: (eax)`= aeax, assuming a is a constant and not a function of x.Justrecognizeany constant drops down to the front.Therefore: (e-ax2)`=-2ae-ax2, treat the negative just as a constant or (-1)For e-ax^2: this one is a little bit trickier:We can just use u-substitution.Let u = x2.u` = 2xIf we substitute the u for x^2, we have: e-au , and we know the deriviate of that is -ae-2au, but we need to multiply by u` as well to get:(-ae-2au)(2x) = -2xae-2au, then we can just plug u back in.u = x2, so:-2xae-2au = -2xae-2ax^2And that is the answer.(e-ax^2)`= -2xae-2ax^2
What is the correct cell notation for the reaction 2Au plus aq plus Cus 2Ausplus Cu2 plus aq?
Cu(s) | Cu2+(aq) Au+(aq) | Au(s)
What happens when chlorine touches gold I know a chemical reaction occurs but how?
Well what chemically happens is an exchage of electrons. In an ionic bond, a metal (gold in this case) reacts with a non-metal (chlorine) to form an ionic compound. So Gold, or Au, most commonly has a charge of 3+. This means that normally to have a full outer shell of electrons, gold needs to give up three electrons, which is a loss of 3 negatives, which gives it a postivie charge. For chlorine to be 'happy' and have a full outer shell, it needs to gain one electron giving it a charge of 1-. These elements will only give up their electrons in specific situations and one is a bond. When chlorine gets put into an area with gold, then the chlorine takes an electron off of the gold, but since gold still needs to lose more electrons, then for every one gold atom losing electrons there must be 3 chlorine atoms taking them away. When this happens yu get a postively charged ion, Au+3 and three negatively charged ions, Cl-1. Since one of these ions is positive and the other negative, they act the same way as two different poles of a magnet would react. They attract to each other and stick together. Since they are now stuck together we know them as the compound AuCl3 or gold (III) chloride. (the III is a roman numeral for one, representing which type of gold was reacting) And that's whats happening when you put some solid gold into a chamber full of chlorine gas!Here is the chemical formula just in case you want to see it:2Au(s) + 3Cl2(g) --> 2AuCl3(s) Also if you are wondering, chlorine comes in pairs in its naturally occurring state, so we have to increase the number of gold around in order to properly react.
What is the aeteriod belts diameter?
The majority of asteroids (majority meaning "more than half") of the asteroids are in a poorly-defined area known as the asteroid belt between the orbits of Mars and Jupiter. That's about - and I really do mean "ABOUT" - 2AU to 4AU from the Sun. If over half of the asteroids are in the asteroid belt, that still leaves a large number of asteroids that are NOT in the asteroid belt, and in fact, asteroids are found almost anywhere in the solar system. And in fact, the month doesn't go by that we don't discover new asteroids just passing VERY close to the Earth. There was one last week (as I write this in July, 2012) that passed within 20,000 miles of the Earth; as close as the geosynchronous orbit satellites!
How do astronomers measure the distance from earth to something in space?
For the Moon they bounce a laser off it and time the return. For space its the change in the light spectrum, I think discovered by Halley. This is similar to the sound of a siren coming and going. This shift lead to the expanding universe theory.___________________________________________For things that aren't too far away, we can measure the parallax by measuring the precise angle to a star at one time, and measure the angle to the star 6 months later when the Earth is on the opposite side of the Sun. That gives us a baseline 2AU long, so we can use geometry to calculate the distance.For things farther away, there is a measure of guesswork involved. By measuring the light spectrum of the star, we can come close to figuring out how hot the star is, and if we know how hot it is, we can calculate how bright it really is. Compare the star's absolute magnitude (how bright it really is) to its visual magnitude (how bright it appears to be) and we can make a good estimate of how far away the star is.This is where an interesting class of stars called "Cephid Variables" come in. They get periodically brighter and dimmer on a regular basis. Astronomers have calculated a relationship between how bright this particular type of star is with the time that it takes to vary in brightness, so we can use these stars as a measuring stick to compare other stars.
How many astronomical unit are in 1 parsec?
About 206,000 given that 1 parsec is 3.06 x 1013 km and 1 AU is 149.6 x 106 km __________________ 1 Astronomical Unit (AU) is the average distance from the Sun to the Earth, about 150 million kilometers or 93 million miles (approximately). We use AU when we talk about distances between objects WITHIN the solar system. One "parsec", or "parallax-second of arc", is the distance that an object would be (from Earth) if we measure a one second of arc difference in the relative direction of a "nearby" object, measured from one side of the Earth's orbit to the other. That gives us a baseline distance of 2 AU, about 300 million km or 186 million miles. You can calculate the distance of one parsec using trigonometry; the base of the triangle is 2AU, and the opposite angle is 1 second of arc (1/3600th of a degree). Roughly, one parsec is about 3.26 light years. We use parsecs to measure distance between stars, or between objects in the galaxy.
Are stars really a known distance away from Earth if their light took years to get to us?
We can only directly calculate the distance to some of the nearer stars using angular parallax. For stars farther away than a few dozen light years, we're mostly guessing based on the brightness of the star; how bright it probably is based on its spectrum, vs how bright it SEEMS to be in the sky. So for example, the north star Polaris is about 430 light years away - plus or minus about 20 LY. So it could be anywhere between 410 and 450 LY. One of the purposes of some of the long-range space probes is to give us a longer baseline for measuring parallax. Once we get two probes about 50AU out from the Sun in each direction, we'll be able to get better calculations of the middle-distance stars. Right now, we're a bit stuck; we can take two views 6 months apart - so that we're on opposite sides of the Earth's orbit - to give us a baseline 2AU long, but if we had two space telescopes out past Pluto in opposite directions, we could have a baseline that was 100AU long. This would give us MUCH more accurate distances to the nearer stars. ----- All stars that can be individually identified will reside within the Milky Way Galaxy. Although the time taken to reach us may have taken a period of time, because they reside within the Milky Way, we would also have moved within that same period, keeping the relative distances about equal. There may be a slight difference, as one star may drop into a lower orbit, but over a period of only 70,000 years [The furthest individual known star] the difference will be negligible. Now galaxies is another thing entirely.
