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You would start by simply writing your reactants and products out, noting this is a double replacement reaction.

BaCl2 + Li2SO4 -----> BaSO4 + LiCl

Then you would need to go back and balance the equation. Note in the above that there are two chloride ions on the left but only one on the right. This can be balanced by placing a coefficient of 2 in front of LiCl.

BaCl2 + Li2SO4 -----> BaSO4 + 2LiCl

This is now a balanced equation.

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Q: What is the net ionic equation for lithium sulfate plus strontium chloride?
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