You would start by simply writing your reactants and products out, noting this is a double replacement reaction.
BaCl2 + Li2SO4 -----> BaSO4 + LiCl
Then you would need to go back and balance the equation. Note in the above that there are two chloride ions on the left but only one on the right. This can be balanced by placing a coefficient of 2 in front of LiCl.
BaCl2 + Li2SO4 -----> BaSO4 + 2LiCl
This is now a balanced equation.
there are no co efficents infront of any of the reactants or products
aqueous strontium sulfide
211 is the mass in grams of 1.15 moles of strontium sulfate.
SrSO4
Strontium Nitrate + Sodium Carbonate→ Strontium Carbonate + Sodium Nitrate Sr(NO3)2(aq) + Na2CO3(aq) → SrCO3(s) + 2NaNO3(aq)
Because strontium sulfate is much less soluble in water than strontium chloride, sodium chloride, or sodium sulfate, this reaction is: Na2SO4 (aq) + SrCl2 (aq) => 2 NaCl (aq) + SrSO4 (s).
Complete ionic equation is:2Li^+(aq) + SO4^2-(aq) = Sr^2+(aq) + 2Cl^-(aq) ==>2Li^+(aq) + 2Cl^-(aq) + SrSO4(s)
there are no co efficents infront of any of the reactants or products
Examples of salts: sodium chloride, uranyle nitrate, potassium acetate, strontium iodide, ammonium phosphate, lithium fluoride, magnesium sulfate, boron fluoride
aqueous strontium sulfide
There is no equation in the question, only two pair of two reactants.
Strontium bromide and potassium sulfate will produce a precipitate of strontium sulfate.
lithium carbonate + sulfuric acid = lituim sulfate + water + carbon dioxide
No reaction occurs
The four MAIN IONS in seawater in descending order of abundance are: CI: Chloride Na: Sodium SO4: Sulfate Mg: magnesium Found in Leckie-Yuretich: Investigating the Ocean, Page 114, Seawater Salinity: The salt of the Ocean
The equation is:Ba+ + (SO4)2- = BaSO4(s)
Lithium Hydrogen Sulfate