1 electron in the s orbital
Hydrogen.
here r the possisble answers: both atoms lose 1 electron a covalent bond forms metal gains an electron and the nonmetal loses an electron metal loses an electron and non metal gains an electron
No, it's actually quite a light metal. It's atomic number is 4, and has a density under 2 g/cm3. For reference most steels are closer to 8 g/cm3, and a heavy metal like Mercury has a density over 13 g/cm3.
1[ml]-----1[cm3] 25[ml]----X X= 25[cm3]
1 electron in the s orbital
A cesium atom has 1 valence electron. It is an alkali metal, and all alkali metals have 1 valence electron. The electron configuration for cesium is (Rn)7s1. The single electron in the 7s sublevel is its valence electron.
Hydrogen has 1 electron. It can easily gain or lose electron to form metal or non metal
It only floats if the density of the metal used is less than 1 gm/cm3
Hydrogen
Hydrogen.
If its mass is 0.6 g and its volume is 1 cm3 , then its density is 0.6 g per cm3 .
It depends on the density of the metal.
Density of uranium: 19,1 g/cm3 1 cubic inch = 16,38706 cm3 The mass of 1 cubic inch of uranium is 313 g.
Since it has 1 valence electrons it is a metal and also non metal because it may loose 1 electron to stabilize or also gain 1 electron to stabilize. Metals loose electrons and non-metals gain electron and hydrogen have both metallic (to loose) and non-metallic (to gain) properties.
The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7
here r the possisble answers: both atoms lose 1 electron a covalent bond forms metal gains an electron and the nonmetal loses an electron metal loses an electron and non metal gains an electron