(Ne) 3S2 3P1
[Ne] 3s2 3p1
Aluminum (Al) follows the configuration of the noble gas before it, neon (Ne). Aluminum has 3 electrons in the 3rd level. Two of them are in the 3s subshell and the other is in the 3p subshell.[Ne]3s23p1
Aluminum has 13 electrons. To achieve a noble gas electron configuration like neon, aluminum needs to lose 3 electrons to have the same electron configuration as neon (10 electrons). This results in the formation of the Al3+ ion.
aluminium should lose three electrons to attain noble gas configuration
Aluminum is [Ne]3s23p1 Sulfur is [Ne]3s23p4
An element that would have to lose three electrons to achieve a noble gas electron configuration is aluminum (Al). Aluminum has 13 electrons, and if it loses three electrons, it would have the same electron configuration as neon (10 electrons), which is a noble gas.
It is the short hand of electron destribution (electron configuration). Constructed by putting the symbol of the noble gas in the period before the element in brackets and continuing the electron configuration from where the noble gas left off. For example: the noble gas distribution of Aluminum is [Ne] 3s2 3p 1
The noble gas electron configuration of radon is [Xe]4f145d106s26p6.
The "Noble gas electron configuration," or the condensed electron configuration, for F is [He] 2s2 3p5.
The noble gas configuration of oxygen (O) is [He] 2s^2 2p^4, where [He] represents the electron configuration of the nearest noble gas, helium.
Only group 18 elements have noble gas configuration. All other elements lack a noble gas electronic configuration.
The electron configuration of aluminum (Al) in noble gas notation is [Ne] 3s2 3p1. This notation indicates that aluminum has the same electron configuration as neon (Ne) up to the 2p orbital, followed by 3s2 3p1 for the remaining electrons in aluminum.