Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...
94241Pu -> 95241Am + e- + v-e
Not asked but answered for completeness sake, for alpha decay the equation is ...
94241Pu -> 92237U +24He2+
The equation for the alpha decay of 242Pu is:94242Pu --> 92228U + 24He
representing the alpha particle as a helium nucleus.
Curium-242 has 146 neutrons and curium-244 has 148 neutrons. Also the half lives are different.
Plutonium is a silvery metal.- Vickers hardness: 255 - Brinell hardness: 242 - Mohs hardness: cca. 3,7
Standard Heat (Enthalpy) of Formation, Hfo, of any compound is the enthalpy change of the reaction by which it is formed from its elements, reactants and products all being in a given standard state.By definition, the standard enthalpy (heat) of formation of an element in its standard state is zero, Hfo = 0.Standard Molar Enthalpy (Heat) of Formation, Hmo, of a compound is the enthalpy change that occurs when one mole of the compound in its standard state is formed from its elements in their standard states.Standard Enthalpy (Heat) of Reaction, Ho, is the difference between the standard enthalpies (heats) of formation of the products and the reactants.Ho(reaction) = the sum of the enthalpy (heat) of formation of products - the sum of the enthalpy (heat) of formation of reactants: Ho(reaction) = Hof(products) - Hof(reactants)To calculate an Enthalpy (Heat) of Reaction:Write the balanced chemical equation for the reaction Remember to include the state (solid, liquid, gas, or aqueous) for each reactant and product.Write the general equation for calculating the enthalpy (heat) of reaction: Ho(reaction) = Hof(products) - Hof(reactants)Substitute the values for the enthalpy (heat) of formation of each product and reactant into the equation. Remember, if there are 2 moles of a reactant or product, you will need to multiply the enthalpy term by 2, if molar enthalpies (heats) of formation are used.Standard Enthalpy (Heat) of FormationExample: Standard Enthalpy (Heat) of Formation of WaterThe standard enthalpy (heat) of formation for liquid water at 298K (25o) is -286 kJ mol-1. This means that 286 kJ of energy is released when liquid water, H2O(l), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(l) Hfo = -286 kJ mol-1The standard enthalpy (heat) of formation of water vapour at 298K (25o) is -242 kJ mol-1.This means that 242 kJ of energy is released when gaseous water (water vapour), H2O(g), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(g) Hfo = -242 kJ mol-1
Oxygen is responsible for the absorption of solar radiation with a wavelength less than 242nm. UV radiation splits oxygen into atoms and the atoms combine with other oxygen molecules to form ozone. Generally, all multi-atom?æ compounds are capable of absorbing UV radiation when the wavelength is short.
Polonium chemical properties Polonium with the atomic number 84 is in the group 16 and period 6 of the periodic table of Mendeleev. Some compounds of polonium are: PoO, PoO2, PoO3, PoH2, halides as PoX2, PoX4, PoX6 and the strange class of polonides (compounds of polonium with other metals). The Pauling electronegativity is 2. Possible valences are: 2, 4, 5, 6, -2. Polonium physical properties Density: alpha phase: 9,196 g/cm3; beta phase: 9,398 g/cm3 Melting point: 254 0C Boiling point: 962 0C Heat of fusion: 13 kJ/mol Heat of vaporization: 102,91 kJ/mol Molar heat capacity: 26,4 J/mol.K Electrical resistivity: 0, 40 microohm.meter Thermal conductivity: 20 W/m.K Atomic radius (empirical): 168 pm First ionization energy: 812,1 kJ/mol Crystalline structure: alpha-phase: cubic; beta phase: rhombohedral Magnetism: monmagnetic Thermal expansion: 23,5 microm/m.K
The nuclear reaction is: 242Cm + 4He = 245Cf + n
The nuclear reaction is: 242Cm + 4He = 245Cf + n
The nuclear reaction is: 242Cm + 4He = 245Cf + n
The reaction is:Pu-239 + alpha = Cm-242 + n
I suppose that the isotope formed is Am-245.
Americanium
The first nuclear reaction to obtain curium was:Pu-239 + He-4 = Cm-242 + nNow curium is separated from burned nuclear fuels.
The first nuclear reaction to obtain curium was:Pu-239 + He-4 = Cm-242 + nNow curium is separated from burned nuclear fuels.
I suppose that the isotope formed is Am-245.
The first nuclear reaction to obtain curium was:Pu-239 + He-4 = Cm-242 + nNow curium is separated from burned nuclear fuels.
x2/242-y2/62=1
x2/242-y2/62=1