4291Mo => 4191Nb + e+ + ve
Hope this works for you!
The four types of nuclear decay are alpha decay, beta decay, gamma decay, and neutron decay. Alpha decay involves the emission of an alpha particle, beta decay involves the emission of beta particles (either electrons or positrons), gamma decay involves the emission of gamma rays, and neutron decay involves the emission of a neutron.
All nuclear decay is spontaneous.
The nuclear decay equation for Po-208 is: Po-208 → Pb-204 + He-4
36 Kr 81 à -1 e o + 37 Rb 81
My book does not list 250Am, nor the product 246Np. Beta decay would probably be preferred in this case over alpha.250Am --> 246Np + 4He
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
Natural chromium is stable and does not decay/
Energy and electrical charge are two quantities that are always conserved in nuclear decay equation.
The nuclear equation for the decay of Po-210 undergoing 2 alpha decays followed by a beta decay and another alpha decay is: Po-210 -> Pb-206 + 4 He-4 + 2 e-1 + 2 v This equation represents the series of decays that result in the transformation of Po-210 into Pb-206, with the emission of two helium nuclei (alpha particles), two electrons, and two neutrinos.
The decay equation is:Co-60----------------------Ni-60 + e-
The equation for the beta decay of 17F: 917F --> 817O+ 10e + ve where the 10e is a positive beta particle or positron.
The equation for the beta decay of 14C: 614C --> 714N + -10e where the e is an electron.