he following equation is balanced 4Al 3O2 -- 2Al2O3 is not a balanced equation.on the reactants side we haev 4 atoms of Al and we have 24 atoms of oxygen.
but on products side we have 24Al but 6 atoms of oxygen.this violates conservation of mass.
The coefficient, 4, times the subscripts, 2 and 3.
so,
8 aluminum atoms.
12 oxygen atoms.
Combination Reaction.
The formula for aluminum nitrate is Al(NO3)3, so there are 9 oxygen atoms. Multiply the number of oxygen atoms inside the parentheses times the subscript outside the parentheses.
Two aluminum atoms and three oxygen atoms >
1 formula unit of aluminum sulfate has the formula Al2(SO4)3. So there are 2 atoms of aluminum, 3 atoms of sulfur and 12 atoms of oxygen in 1 formula unit of aluminum sulfate. There are no molecules of aluminum sulfate. They are called formula units.
Mass of Aluminum Sulfate: 2.74g Molar Mass of Aluminum Sulfate: 342.14 g/mol Therefore, number of moles of Oxygen can be calculated by 2.74g * 12/342.14 g/mol = 0.096 moles Now since u have the moles of Oxygen, the number of oxygen atoms is given by 0.096 mol * (6.02*10^23) particles or atoms/mol that gives u about 5.78 * 10^22 atoms of oxygen
Aluminum loses three electrons to have a full valence shell. Oxygen gains two electrons to have a full valence shell. Aluminum Oxide is shown as Al2O3 because there are three oxygen atoms with a total of 6 gained electrons. Two Aluminum atoms lose 6 electrons and three Oxygen atoms gain six. This is the balance between aluminum and oxygen.
The formula for aluminum chromate is Al2(CrO4)3, so there are 12 oxygen atoms. Multiply the number of oxygen atoms inside the parentheses times the subscript outside the parentheses.
The formula for aluminum nitrate is Al(NO3)3, so there are 9 oxygen atoms. Multiply the number of oxygen atoms inside the parentheses times the subscript outside the parentheses.
2 aluminum atoms 4 sulphur atoms 4 oxygen atoms
There are 13 protons in aluminum and 13 electrons. So, there are 13 atoms in aluminum. In oxygen, there are 8 protons and 8 electrons. thus there are 8 atoms. EDIT: This answer is absolutely and completely incorrect. (Dr.J.)
Three atoms of oxygen are required to react with each two atoms of aluminum to form the most common product of reaction between oxygen and aluminum. Therefore, 0.75 mole of oxygen atoms will be required to react with 0.5 mole of aluminum atoms. The atomic weight of oxygen is 15.999; therefore, the mass will be (0.75)(15.999) = 12 grams of oxygen, to the maximum possibly justified number of significant digits.
Two aluminum atoms and three oxygen atoms >
1 formula unit of aluminum sulfate has the formula Al2(SO4)3. So there are 2 atoms of aluminum, 3 atoms of sulfur and 12 atoms of oxygen in 1 formula unit of aluminum sulfate. There are no molecules of aluminum sulfate. They are called formula units.
Mass of Aluminum Sulfate: 2.74g Molar Mass of Aluminum Sulfate: 342.14 g/mol Therefore, number of moles of Oxygen can be calculated by 2.74g * 12/342.14 g/mol = 0.096 moles Now since u have the moles of Oxygen, the number of oxygen atoms is given by 0.096 mol * (6.02*10^23) particles or atoms/mol that gives u about 5.78 * 10^22 atoms of oxygen
Aluminum loses three electrons to have a full valence shell. Oxygen gains two electrons to have a full valence shell. Aluminum Oxide is shown as Al2O3 because there are three oxygen atoms with a total of 6 gained electrons. Two Aluminum atoms lose 6 electrons and three Oxygen atoms gain six. This is the balance between aluminum and oxygen.
there are four.
There are 12 oxygen atoms in a molecule of aluminum sulfate. The formula for aluminum sulfate is Al2(SO4)3. This tells us there are 3 sulfate ions, each with 4 oxygen atoms per sulfate, so 3 * 4 = 12.== ==
The number of atoms in 1,2 moles of pure aluminum is 7,2265690284.1023.