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.02 btu
because it has a great heat capacity
The pressure of the atmosphere around the water determines the temperature at which it boils. Also, the presence of dissolved particles in the water will raise the boiling temperature.Dissolved solids (salt, sugar or anything else in there, This will raise the temperature). Pressure lower pressure means less temperature needed to boild the warer. (altitue on earth will do this cause higher altitudes means lower pressureDissolved solids (salt, sugar or anything else in there, This will raise the temperature). Pressure lower pressure means less temperature needed to boild the warer. (altitue on earth will do this cause higher altitudes means lower pressure
1 calorie is needed to raise 1 g of water 1 °C. 350 * 22 = 7700 calories ■
No chemicals needed: just raise the temperature. Melting is never a chemical change, but purely physical!
q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules
It would depend on the temperature of the water, or average kinetic energy. (KE) However, what you may be looking for is how much heat is needed to raise the KE, or temperature, of water. 4.184 kilojoules per gram is the heat required to raise the temperature of water 1 degree Celsius.
A heater can raise the temperature of a fish tank if needed
Mass, heat capacity, the desired raise in temperature.
The number of calories required will depend on the mass of water which is to be heated.
initially at-10.0 c, the steam at 115 c. in kilojoules,is required to ralse the temperature of 2.50 kg HG from 20.0 to 6.0 c
raise the temperature of the body by 1 Celsius
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
The needed energy is 10 calories.
.02 btu
42 j
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================