CO2's molecular weight is 44 so 44 g of CO2 contain Avogadro's number of CO2 molecules. 20 g would contain 20/44 x Avogadro's number.
C + O2 ------> CO2 is the reaction equation. 1 mole of C + 1 mole of O2 makes 1 mole of CO2.
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2= 44.0 grams1.50 moles CO2 × (44.0 grams) = 66.0 grams CO2
44.01
Balanced equation C2H4 + 3O2 -> 2CO2 + 2H2O 125 grams ethylene (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 moleCO2) = 392 grams CO2 formed ==================
The gram molecular mass of carbon dioxide is about 44.01 grams. By definition, this value is the number of grams of carbon dioxide that contains Avogadro's Number ("AN") of molecules. Avogadro's Number is about 6.022 X 10^23. Therefore the number of molecules in 1 gram is (1/44.01)(AN) or 2 X 10^21 molecules, to the justified number of significant digits.
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
pv=nrt. The volume, in litres is calculable by this formula: v=nrt/p, where v is in litres, n is your (1.5x10^25 molecules)/(Avrogadro's 6.022×1023 mol–1), r is a constant with a value of 8.31, t is temperature in Kelvin and p is pressure in Pascals.
One mole is defined by Avogadro's number of 6. 02x10^23 particles. To solve this equation we multiple Avogadro's number by our given quantity of 2. 10 moles. The answer then is 2. 64x10^24 molecules of CO2.
1 mol = 6.02 * 10^23 molecules 0.018 mol = 6.02 * 10^28 * 0.018 molecules 1.0836 * 10^27 molecules of CO2
1 mol = 6.02 * 10^23 molecules 0.018 mol = 6.02 * 10^28 * 0.018 molecules 1.0836 * 10^27 molecules of CO2
C + O2 ------> CO2 is the reaction equation. 1 mole of C + 1 mole of O2 makes 1 mole of CO2.
This can be calculated by using the number of Avogadro. It states that 1 mole is equal to 6.02214179*10^23 molecules. If 1 mole equals 6.02214179*10^23 molecules, then 0.0180 mole equals to: 0.0180 * 6.02214179*10^23 = 1.083985522*10^22 CO2 molecules.
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams33.0 grams C / (44.0 grams) = .750 moles CO2
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
1 mole CO2 = 6.022 x 1023 molecules 2.4mol CO2 x 6.022 x 1023 molecules CO2/1mol CO2 = 1.4 x 1024 molecules CO2
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2= 44.0 grams1.50 moles CO2 × (44.0 grams) = 66.0 grams CO2