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44.01

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Zackery Schumm

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2y ago
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13y ago

You must use the Ideal Gas Law to calculate the number of moles of CO2 and then convert the number of moles of CO2 to a mass in grams. Here it is:

PV=nRT @STP, P = 1atm, T= 273K, R = .08206 L atm K-1 mol-1

1(1.6)=n(.08206)(273)

1.6=22.4n

n=14 moles CO2.

14 moles CO2 x 44.01grams/1 mole CO2 =620 grams CO2(considering significant figures).

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14y ago

1.5L x 1 mole CO2/22.4L x 44g CO2/1 mole CO2 = 2.9g CO2 @ STP

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7y ago

5,52 L of carbon dioxide is equivalent to 10,91 g.

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11y ago

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Q: How many grams of carbon dioxide gas are present in 5.52 liters at STP?
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