44.01
You must use the Ideal Gas Law to calculate the number of moles of CO2 and then convert the number of moles of CO2 to a mass in grams. Here it is:
PV=nRT @STP, P = 1atm, T= 273K, R = .08206 L atm K-1 mol-1
1(1.6)=n(.08206)(273)
1.6=22.4n
n=14 moles CO2.
14 moles CO2 x 44.01grams/1 mole CO2 =620 grams CO2(considering significant figures).
1.5L x 1 mole CO2/22.4L x 44g CO2/1 mole CO2 = 2.9g CO2 @ STP
5,52 L of carbon dioxide is equivalent to 10,91 g.
Bonn
88
80,0 moles of CO2is equal to 3 520,8 g.
One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ration of isotopes equal to that in nature - has a mass of 12.0107 grams.
We need 14,8 g oxygen.
A small bus can emit 270 grams of carbon dioxide per kilometre. (Australian figures). This might be the equivalent of about 21 tonnes of Carbon dioxide (CO2) a year for a bus driving 60,000 km (36,000 miles).
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
The answer is 19,288 g cacium carbonate.
88
22 grams carbon dioxide (0.5 moles)
6 grams
The mass of carbon dioxide is 141,2 g.
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.
no
80,0 moles of CO2is equal to 3 520,8 g.