0,2 moles contain approx. 1,2.10e+23 atoms, molecules etc.
avagadros number
Since one mole is equal to 6.022x10^23, there are .36 moles in 2.17x10 representative particles of bromine. A mole is a measure used to make atomic calculations for density.
This is equivalent to 0,36 moles.
There are 1.5 x 10^24 representative particles in 2.5 moles, considering Avogadro's number (6.022 x 10^23) representative particles per mole.
In the ideal gas law, n represents the number of moles of gas present in the system. It is a measure of the quantity of gas particles and is used to calculate the amount of gas based on the number of moles rather than individual particles.
1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.
The moles are converted into a number of particles by multiplying 6.02 by 10(with the power of 23)
To calculate the number of moles of particles present in a sample, you need to divide the sample's mass by the molar mass of the particles. If you specify the particles as N'O, you should provide the molar mass of N'O for an accurate calculation.
One mole of any substance contains Avogadro's number of representative particles. Avogadro's number is 6.02x1023. So, if you have 2.8 moles of something, you multiply that number by Avogadro to get 1.69x1024.
Yes, the coefficients in a balanced chemical equation represent the ratio of moles of reactants and products involved in the reaction. They do not directly represent the number of individual particles, but they do correspond to the number of moles of particles involved in the reaction according to the stoichiometry of the reaction.
Moles are an extensive property. Extensive properties depend on the amount of substance present, and moles measure the quantity of particles (atoms, molecules, etc.) in a sample. Therefore, as the amount of substance increases, the number of moles also increases.
No