1s2 2s2 2p6 3s2 3p6
2, 8, 18, 18, 1
⬆⬇1s ⬆⬇2s ⬆2p 2p should look like _ _ _ 2p
The number of electrons in the orbitals are as follows:Shell 1: 2Shell 2: 8Shell 3: 18Shell 4: 18Shell 5: 8
Well, I can't draw a diagram for you here, but the electron configuration is: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f9 Wikipedia has a nice diagram here: http://en.wikipedia.org/wiki/File:Electron_shell_097_Berkelium.svg
Boron has:- 1s2 2s2 2p1
B
Boron has 2 shells altogether. 2 electrons on the first one and the remaining three on the second. Altogether boron (B) has 5 electrons.
Electronic configuration of boron: [He]2s2.2p1.
orbital diagram for F
Because in Boron there is a complete 2s orbital and the increased shielding of the 2s orbital reduces the ionisation energy compared to that seen in Beryllium.
1s2 2s2 3p4 3d1
LL
An orbital diagram is used to show how the orbitals of a subshell areoccupied by electrons. The two spin projections are given by arrowspointing up (ms =+1/2) and down (ms = -1/2). Thus, electronicconfiguration 1s22s22p1 corresponds to the orbital diagram:
The orbital diagram for MAgnesium is
Boron has 5 electrons and protons. Its Bohr diagram link is added in the related links.
Yes, if the orbital is the outermost one that includes the valence electrons. Aluminum, for example, is such an atom, as is boron.