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Second order.

If the half life of a reaction is halved as the initial concentration of the reactant is doubled, it means that half life is inversely proportional to initial concentration for this reaction.

The only half life equation that fits this is the one for a second-order reaction. t(1/2) = 1/[Ao]k

As you can see since k remains constant, if you double [Ao], you will cause t(1/2) to be halved.

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Q: What is the order of reaction if the half life of a reaction is halved as the initial concentration of the reactant is doubled.?
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