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In VO vanadium has an oxidation number of +2 and O an oxidation number of -2

Just in case you missed the 2+ , in vanadyl ion VO2+ V has the oxidation number of +4, O has -2

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11y ago
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10y ago

The oxidation number of V and O in the compound V2O7-4 is vanadium/known oxidation state x 20(7th power)- 4. There are oxidation numbers for most if not all compounds.

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3y ago

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Q: What is oxidation number of V and O in V2O7-4?
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