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(NH4)2CO3 is neutral. Therefore, it means that the total charge on this compound will equal to zero. N=-3, H=+1, C=4, O=-2

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11y ago
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11y ago

-2 for each oxygen (O), +5 for each vanadium (V)

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13y ago

-1, 0, 1, 2, 3, 4 and 5 oxidation states

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6y ago

The molecule is neutral.

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15y ago

Five.

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Q: What is the oxidation number for ammonium sulfate?
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