Assuming you mean what is the oxidation number of each atom in the compound C3H8O? Oxidation rules state the the sum of all oxidation numbers in a neutral molecule equals 0.
1. O = -2
2. H = +1
3. C = -2
These numbers are derived from...
(-2) + (+1 x 8) + (-2 x 3) = 0
The middle carbon atom is bonded with two other carbon atoms and two hydrogen atoms, therefore +2 oxidation number. The other two carbon atoms are bonded with three hydrogen atoms and a carbon atom. There oxidation numbers are equal to +3.
This compound is propane. C shows +2 and +3 oxidation numbers.
-3 on the first C and +3 on the second C.
The oxidation state or number of C
Oxidation number of C is +3. Oxidation number of O is -2.
the oxidation number is 0
Since H6 = +1 x6 = +6 and O= -2 . You are left with +4, therefore each C atom has -2
Oxidation number is 4, formula C3O2O=C=C=C=O
C is +4, each oxygen is -2
There are two C atoms. One show s-3 and other shows +3.
Oxidation number of C is +3. Oxidation number of O is -2.
the oxidation number is 0
Since H6 = +1 x6 = +6 and O= -2 . You are left with +4, therefore each C atom has -2
Oxidation number is 4, formula C3O2O=C=C=C=O
C is +4, each oxygen is -2
The oxidation number is + for C and -2 for O.
Oxidation number of Li is +1. It is -2 in O and +4 in C
4+
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.
Formaldehyde is a aldehyde. Oxidation number of C is +2.
O.S. of C = +4